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bazaltina [42]
2 years ago
10

Find the equation of a line in slope-intercept form with a slope of 5 that contains the point (3,8).

Mathematics
2 answers:
devlian [24]2 years ago
7 0

Answer:

y = 5x - 7

Step-by-step explanation:

y = mx + c

y = 5x + c

to find c, input given coordinates

8 = 5 x 3 + c

8 = 15 + c

-c = 15 - 8

-c = 7

c = -7

put that all together and you get:

y = 5x - 7

Step2247 [10]2 years ago
3 0
The answer would be y=5x+8
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How to solve this? ​
nevsk [136]

Answer:

Answer of 17 is ㏒(x^{2}+15x), Answer of 33 is x = 8 , Answer of 35 is x = ㏒10/㏒2 , Answer of 37 is  x = -㏒12/㏒8 and Answer of 39 is x = 5

Step-by-step explanation:

17. ㏒x + ㏒(x+15)

     Using property ㏒a + ㏒b = ㏒a×b

     ∴ ㏒x + ㏒(x+15)

        ㏒x×(x+15)

        ㏒(x^{2}+15x)

        The answer is ㏒(x^{2}+15x)

33. 2^(x-5) = 8

     2^(x-5) = 2^3

      Using property 2^a = 2^b

      Then a = b

     ∴x-5 = 3

       x = 8

      The answer is x = 8

35. 2^x = 10

    Taking log on both sides gives

     ㏒2^x = ㏒10

     x×㏒2 = ㏒10

     x = ㏒10/㏒2

    The answer is x = ㏒10/㏒2

37. 8^-x = 12

    Taking log on both sides gives

     ㏒8^-x = ㏒12

     -x×㏒8 = ㏒12

      x = -㏒12/㏒8

    The answer is  x = -㏒12/㏒8

39. 5(2^3 × x) = 8

      5(8×x) = 8

      x = 5

    The answer is x=5

 

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Step-by-step explanation:

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Step-by-step explanation:

The numerator is 13

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r = - 13 / 15 inches/week

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