Question

A packet switch has 5 users, each offering packets at a rate of 10 packets per second. The average length of the packets is 1,024 bits. The packet switch needs to transmit this data over a 56-Kbps WAN circuit. Calculate the load and utilization of the link.

Answer 1

The load and utilization of the link will be, respectively, 51200bps and 91,4%.

What is a WAN circuit?

Wide Area Network (WAN) is a communication network that covers a large geographic area, such as cities, states and even countries. This type of connection is usually the result of joining smaller networks, such as several LANs (Local Area Networks).

While LANs are able to integrate devices, documents, data, software and hardware in a geographically small space, to facilitate the exchange of information wide area networks (WAN) are able to integrate multiple local area networks. In this way, the integration between devices, documents and important data of a company or institution can take place even between geographically very distant regions.

That being said, to calculate the load it is necessary to multiply users, packets and bits. So:

$5.10.1024 = 51200bps$

And to calculate the utilization it is necessary to divide load per transmission. So:

$51200/561000 = 0,914$ or 91,4%

See more about WAN circuit at: brainly.com/question/621746

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