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Elanso [62]
4 years ago
15

You have recently implemented a new WAN technology to connect a remote branch office to your headquarters. While making VoIP cal

ls between the offices, employees complain about delays between someone talking and the other party hearing what they've said. Which WAN technology is most likely to cause this apparent latency?
Computers and Technology
1 answer:
sergejj [24]4 years ago
5 0

Answer:

Satellite is the correct answer to the given question .

Explanation:

Connections via the  satellite deliver the communication in the whole  world environment .The  reliability, expense and the performance problems have long suffered satellite connections, rendering the satellite-based WAN connections are just under the suitable.

The satellite wan connection is the Linking of  the head office to a remote branch office.The satellite wan technology  allowing the VoIP calls between both the departments .When the workers complain about discrepancies between something talking as well as the other person learning.

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Write a function named repeat_words that takes two string parameters: 1. in_file: the name of an input file that exists before r
madam [21]

Answer:

#section 1

def repeat_words(firstFile, secondFile):

   infile_1=open(firstFile,'r')

   content1=infile_1.read()

   infile_1.close()

#section 2

   import string

   newContent=""

   for char in content1:

       newContent+=char.strip(string.punctuation)

   newContent=newContent.lower()

   newContent=newContent.split()

#section 3

   repeated_list=[]

   for word in newContent:

       if newContent.count(word)>1:

           repeated_list.append(word)

#section 4

   new_repeat_list=[]

   for item in repeated_list:

      while item not in new_repeat_list:

         new_repeat_list.append(item)

#section 5

   outfile=open(secondFile,'w')

   for repeat in new_repeat_list:

       outfile.write(repeat)

       outfile.write('\n')

   outfile.close()

   infile_2=open(secondFile,'r')

   content2=secondFile.read()

   infile_2.close()

   return content2

# section 6

in_file = 'aa.txt'

out_file = 'cpu.txt'

print(repeat_words(in_file, out_file))

Explanation:

#section 1

it defines a function that takes two arguments. It opens the first argument in the read mode and stores all it's content in a string variable "content1". finally the file is closed.

#section 2

In this section the string module is imported which allows for easy manipulation of string variables.

A new string variable is created that would store the already stripped file.

<em>strip(string.punctuation)  </em>strips every character of any leading or trialing punctuation.

<em>lower()  </em>converts string to lover case.

<em>split() </em>converts a string to an array of sub-string, i.e an array of words.

#section 3

This section collects all the words in the array and places them in a list.

#section 4

Utilizes a For and a While loop to ensure that no word repeats and stores it in a new list.

#section 5

Opens a new file and writes all the content into that new file and then closes the file.

re-opens the file, reads and returns the content of the file.

# section 6

This is added in order to test the function and print the result

I used your question to test the function and attached the result.

cheers!

8 0
3 years ago
Count positive and negative number and compute the average. The program will have the user input an unspecified number of intege
Alla [95]

Answer:

The solution code is written in Python 3

  1. total = 0
  2. count = 0
  3. neg = 0
  4. pos = 0
  5. num = int(input("Enter an integer: "))
  6. while(num != 0):
  7.    total += num  
  8.    count += 1
  9.    if(num < 0):
  10.        neg += 1
  11.    else:
  12.        pos += 1
  13.    num = int(input("Enter an integer: "))
  14. print("The number of positives: " + str(pos))
  15. print("The number of negatives: " + str(neg))
  16. print("The total is " + str(total))
  17. print("The average is " + str(total/count))

Explanation:

Firstly, we create four variables, <em>total</em> , <em>count,</em> <em>neg</em> and <em>pos </em>(Line 1- 4). This is to prepare the variable to hold the value of summation of input integer (<em>total</em>), total number of input number (<em>count</em>), total negatives (<em>neg</em>) and total positives (<em>pos</em>).

Next, we prompt user for the first integer (Line 6).

Create a sentinel while loop and set the condition so long as the current input number, <em>num</em> is not equal to zero. the program will just keep adding the current <em>num</em> to total (Line 9)  and increment the count by one (Line 10).

if <em>num</em> smaller than zero, increment the <em>neg</em> by one (Line 13) else increment the <em>pos </em>by one (Line 15). This is to track the total number of positives and negatives.

Finally, we can display all the required output (Line 20 - 23) using the Python built-in function <em>print()</em>  when user enter 0 to terminate the while loop. The output shall be as follows:

The number of positives: 3

The number of negatives: 1

The total is 5

The average is 1.25

3 0
4 years ago
What’s bigger 4,000,000 KB or 2.8 GB
Zanzabum

Answer:2.8 GB is bigeer

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4 years ago
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igomit [66]
Mash-up, I believe, is the correct answer.
5 0
3 years ago
Change the screen resolution so you can view more information on your screen. Use the resolution that enables you to fit the mos
bulgar [2K]
On Windows 10, you are able to right-click the desktop, and select "Display Settings". From there you can see all attached displays that are connected to your computer. Select "Advanced display settings", and your resolution would be right there, for example, the resolution of my monitor is 3840×2160.
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