First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
I think it’s 1.75 sorry if this is wrong
108.55
65% of 167 is 108.55
Brainliest please? :)
Answer:
The answer of this question is (D) 8
Answer:
22
Step-by-step explanation:
Given the following
GE = 3x - 11 FD = 2x
Let us assume GE is parallel to FD, hence GE = FD
3x - 11 = 2x
3x - 2x = 0+11
x = 11
Get GE
GE = 3x - 11
GE = 3(11)-11
GE= 33 - 11
GE = 22
Hence the length of GE is 22
