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forsale [732]
3 years ago
14

Solve for y in the equation 4y+15=-5y+9 a)-6 b) -2/3 c)2/3 d)6

Mathematics
2 answers:
jenyasd209 [6]3 years ago
7 0
Your goal is to isolate y

To begin isolating y, perform the opposite operation by subtracting 15 on both sides of the equation

4y = -5y - 6

Perform the opposite operation by adding 5y on both sides of the equation

9y = -6

Perform the opposite operation by dividing both sides of the equation by 9

y=y= -\frac{1}{3}
galina1969 [7]3 years ago
3 0
First off, you need to have your ys on the same side. Here's how to do it:
4y + 15 = -5y + 9
4y + 5y = 9 - 15 (once a number goes to the other side, it changes its sign)
9y = -6
y = -6/9
y = -2/3

The correct answer is B. -2/3
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Answer:

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Step-by-step explanation:

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SVETLANKA909090 [29]

Answer:

a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $ \pm $ Standard Deviation (SD).

Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $ \frac{68}{100} \times 1200 $

= 68 X 12 = 816.

That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $ \pm $ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $ \frac{95}{2} \% $ of the values.

Therefore, Scores between 72 and 90 = $ \frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200  $

$ \implies 95 \times 12 $ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $ \frac{2.5}{100} \times 1200 $

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

8 0
2 years ago
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Answer:

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