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forsale [732]
3 years ago
14

Solve for y in the equation 4y+15=-5y+9 a)-6 b) -2/3 c)2/3 d)6

Mathematics
2 answers:
jenyasd209 [6]3 years ago
7 0
Your goal is to isolate y

To begin isolating y, perform the opposite operation by subtracting 15 on both sides of the equation

4y = -5y - 6

Perform the opposite operation by adding 5y on both sides of the equation

9y = -6

Perform the opposite operation by dividing both sides of the equation by 9

y=y= -\frac{1}{3}
galina1969 [7]3 years ago
3 0
First off, you need to have your ys on the same side. Here's how to do it:
4y + 15 = -5y + 9
4y + 5y = 9 - 15 (once a number goes to the other side, it changes its sign)
9y = -6
y = -6/9
y = -2/3

The correct answer is B. -2/3
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Firlakuza [10]
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
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The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.



Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

Substituting C(2, 2) into the system we have:
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Part C:
Given that </span><span>Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true

For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true

For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
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7 0
3 years ago
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Virty [35]
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