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DedPeter [7]
2 years ago
11

A bag contains lettered tiles. the theoretical probability of choosing a vowel is 40%. the bag contains 78 consonants. how many

tiles are in the bag?
Mathematics
1 answer:
zepelin [54]2 years ago
5 0

The total number of ties present in the bag are 130.

<h3>What is probability?</h3>

Calculating or estimating how likely something is to occur is what probability is all about. The likelihood of an event occurring can be expressed using words like "certain," "impossible," or "probable."

Formula for probability is -

Probability(Event) = Favourable Outcomes/Total Outcomes

It P(E) is the probability for occurring any event.

'x' be the favourable outcome.

'n' be the total outcome.

Then,

P(E) = x/n.

Calculation for the total tiles present the bag.

The probability of choosing a vowel is 40% = 0.4.

Then, the probability of choosing a consonants will be 1 - 0.4 = 0.6 or 60%.

Let P(E) be the probability of the occurrence of the consonants.

Then,

P(E) = total number of consonants/total tiles in the bag.

Let 'T' be the total tiles in the bag.

0.6 = 78/T

T = 78/0.6

T = 130

Therefore, the total tiles present in the bag are 130.

To know more about the probability, here

brainly.com/question/13604758

#SPJ4

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 You would take a number (lets use 15) and the second number (lets use 5) would determine how many times it would go into 15. In other words, 5 time x would equal 15 (5x=15). 5, being a factor of 15, would evenly fit into 15 three times.
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Every time I use a piece of scrap paper, I crumple it up and try to shoot it inside the recycling bin across the room. I'm prett
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Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

With 5 shoots, the probability of making at least one is \frac{211}{243}, hence the probability of making none, P(X = 0), is \frac{232}{243}, hence:

(1 - p)^5 = \frac{232}{243}

\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}

1 - p = 0.9908

p = 0.0092

Then, with 6 shoots, the parameters are:

n = 6, p = 0.0092.

The probability that at least two of them make it inside the recycling bin is:

P(X \geq 2) = 1 - P(X < 2)

In which:

[P(X < 2) = P(X = 0) + P(X = 1)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.0092)^{0}.(0.9908)^{6} = 0.9461

P(X = 1) = C_{6,1}.(0.0092)^{1}.(0.9908)^{5} = 0.0527

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9988 = 0.0012

0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

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Answer:

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