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Nana76 [90]
3 years ago
14

I need help please I don’t know how to make this can someone help me ?

Mathematics
1 answer:
NISA [10]3 years ago
8 0

Answer:

the simplified answer is 3 3/4

Step-by-step explanation:

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Help please. Middle school math
Zanzabum

Answer:

  • 8 - H
  • 9 - T
  • 10 - D
  • GARFIELD THE CAT

Step-by-step explanation:

Correct so far.

  H -- 8

  T -- 9

  D -- 10

The balloon depicted ...

  GARFIELD THE CAT

_____

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(b·c)

Of course, an odd number of minus signs in a product means the product is negative.

__

Most of these can be figured just by looking at the coefficient, or the exponent of one variable, such as x.

8 0
3 years ago
Y=-x^2+2x+1 how do you get the vertex, and x intercept and the symmetry point to the y intercept
dsp73
In y=ax²+bx+c, the vertex is when x=-b/(2a), 
the x intercept is the value of x when y=0, and the y intercept is the value of y when x=0
in this case, a=-1, b=2, so the vertex is when x=-2/[2*(-1)]=1
when x=1, y=-(1)²+2*1+1=2, so the vertex is (1,2)

when x=0, y=1, the x intercept is (0,1)
when y=0, -x²+2x+1=0, use the quadratic formula to find x: x=-1+√2, x=-1-√2
so the symmetry point the the y intercept is (-1+√2, 0) (-1-√2, 0)
3 0
3 years ago
What restriction should be applied to y = tanx for y = arctanx to be defined?
Dmitrij [34]

Answer:

restrict the domain to (-pi/2, pi/2)

Step-by-step explanation:

edge 2020

3 0
2 years ago
Which of the following illustrates the product rule for logarithmic equations?
Ulleksa [173]
The right answer for the question that is being asked and shown above is that: "log2(4x) = log2 (4) + log2 (x)." The equation that illustrates the product rule for logarithmic equations is that <span>log2(4x) = log2 (4) + log2 (x)</span>
8 0
3 years ago
Read 2 more answers
I need help with this question. I cannot find any equations that work....
lidiya [134]

Answer:

  see the attachments for the graph(s)

  • y = -1/6(x -3)^2 +6
  • y = -1/6(x +3)(x -9)
  • y = -1/6x^2 +x +9/2

Step-by-step explanation:

1) The point at (3, 6) is on the vertical line that is halfway between the zeros at x=-3 and x=9, so it represents the vertex of the function. That knowledge, with any of the other points, lets you write the vertex form of the equation.

  y = a(x -3)^2 +6

Using the point (0, 4.5), we can find the value of 'a':

  4.5 = a(0 -3)^2 +6

  -1.5 = 9a

  -1.5/9 = a = -1/6

So, the vertex form of the equation is ...

  y = -1/6(x -3)^2 +6

A graph of this is shown in the attachment.

__

2) Now that we know the leading coefficient is -1/6, we can write the equation in "intercept form" (factored form) as ...

  y = -1/6(x +3)(x -9)

In this form, each zero (p) gives rise to a factor (x-p).

The second attachment shows the graph of this.

__

3) We can also write the equation in standard form, by expanding the one in (2) above:

  y = -1/6(x^2 -6x -27)

  y = -1/6x^2 +x +9/2

The third attachment shows the graph of this.

8 0
3 years ago
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