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1 year ago

3 rhombi are connected at a point, side by side. All sides are congruent.

Mathematics

1 answer:

never [62]1 year ago

6 0

a. The amount of paper that he is going to need would given as 12 square inches.

b. If it is 11 inches what is needed to cover the wall is given as 396

<h3>a. How to solve for the amount of paper needed</h3>

We have the area of a rhombus to be given as

0.5 *d1 * d2

We have d1 = 6 inches

d2 = 4 inches

then area would be

0.5 * 6 * 4

= 12 inches

b. The amount of paper used as length is 11 feet long

1 ft = 12 inches

then 11 feet = 11 * 12

= 132

Number needed = 4

132/4 = 33

Then the area would be 33 * 12 inches to cover the wall

= 396

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Which expression is equivalent to 10x²y + 25x^2

r-ruslan [8.4K]

Answer:

5x²(2y + 5)

Step-by-step explanation:

10x²y + 25x²

to start we have to express the parts of the function as multiplication

2*5*x²*y + 5*5*x²

then we have to see that they have both parts of the sum in common, and what they have in common we get out of common invoice and what is left we add together.

5x²(2y + 5)

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3 years ago

32 is 25% of x. Hurry please

kondor19780726 [428]

The answer is 128

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3 years ago

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3 years ago

Suppose that 10 < n < 11. A possible value for n is

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$10 < n < 11 \\$
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Possible value can be easily obtained by generating an arithmetic mean

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Else we've infinite numbers between them ,
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3 years ago

HELP!!!! I cannot find any good answers for this question and I keep getting it wrong! The answer options are:

kondaur [170]

The missing reason is (d) Add the fractions together on the right side of the equation

<h3>How to complete the missing reason?</h3>

From the statements, we have the following equation:

x^2 + b/a x + (b/2a)^2 = -4ac/4a^2 + b^2/4a^2

Next, we add the fractions on the right-hand side of the equation.

This gives

x^2 + b/a x + (b/2a)^2 = [-4ac + b^2]/4a^2

The above means that the last statement is gotten by adding the fractions on the right-hand side of the equation.

Hence, the missing reason is (d) Add the fractions together on the right side of the equation

Read more about quadratic equations at:

brainly.com/question/1214333

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2 years ago