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anastassius [24]
3 years ago
10

Some help please stuck on 4, 8, 9

Mathematics
1 answer:
bulgar [2K]3 years ago
6 0
4:
a) if a cloud is a mid-level cloud, then it is between 6,500 and 20,000 feet.
b) if a cloud isn't a mid level cloud, then it is not between 6,500 and 20,000 feet. [I don't know if this statement is true]
8:
P=2l+2w
solve for w means to make the equation like w=... (get w on one side by itself).
First, subtract 2l from both sides
P-2l=2w
Now, divide both sides by 2
{P-2l}{2} = W
Done
9:
*The question is a bit wrong here; it should have said In the corner of the angle ABC there is a little square symbol - that means it is a 90 degree angle.
The angle ABC is broken up into angles ABD and DBC, so ABD and DBC add up to 90 degrees.
So, we can make the equation (2x + 10) + (x + 14) = 90
Then solve
Since it is all addition, the parentheses are unnecessary
2x + 10 + x + 14 = 90
Add all x terms together, and the numbers together
3x + 24 = 90
Subtract 24 from both sides
3x = 66
Divide both sides by 3
x = 22
Now, plug in this x value into the formulas for the two angles
ABD = 2(22) + 10 = 44+10 = 54 degrees
DBC = 22 + 14 = 36 degrees
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So it will look like:

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sukhopar [10]

Answer:

From the result of the one-tailed z-test, we can conclude that the mean waiting time is not significantly less than the the 15 minute claim by the taxpayer advocate.

Step-by-step explanation:

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Mean waiting time = 13 minutes

Standard deviation = 11 minutes

We need to perform one hypothesis test that the actual mean waiting time turned out to be significantly less than the 15-minute claim made by the taxpayer advocate.

The null hypothesis would be that there is no significant difference.

H₀: μ₀ = 15 minutes

The alternative hypothesis would be that the mean waiting time is indeed significantly less than the 15-minute claim by the taxpayer advocate.

Hₐ: μ₀ < 15 minutes.

This is evidently a one tail hypothesis test (we're investigating only in one direction; less than the claim). Hence, we can use the z-test

z = (x - μ)/σₓ

σₓ = (σ/√n) = (11/√50) = 1.556

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Using the z-table at significance level of 0.05.

p-value = 1 - 0.9115 (from the z-tables)

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Since the p-value is more than the significance level (0.0885 > 0.05), we do not reject the null hypothesis.

Hence, we accept the null hypothesis and can conclude that the mean waiting time is not significantly less than the the 15 minute claim by the taxpayer advocate.

Hope this Helps!!!

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