Answer:
Veterinary science deals with the health and wellbeing of animals
Y'know it’s basically a veterinarian.
Explanation:
PogChamp
It is True.
Inflammation of the small intestine caused by eating or drinking substances contaminated with viral or bacterial pathogens is called enteritis.
<h3>What is called inflammation?</h3>
Inflammation is a necessary aspect of the healing process in your body. It happens when inflammatory cells migrate to the site of an injury or foreign substance, such as bacteria. Chronic inflammation may result if inflammatory cells remain for an extended period of time.
<h3>What causes inflammation of the small intestine?</h3>
The inflammation of your small intestine is known as enteritis. It might also affect your stomach (gastroenteritis) or colon (enterocolitis). It is frequently the result of a viral, bacterial, or parasitic illness (food poisoning, stomach bug or the stomach flu). It can be caused by radiation, medications, or illness.
To learn more about inflammation from the given link
brainly.com/question/14673970
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If a child has been diagnosed as having failure to thrive then the nurse should use half-strength formula when feeding the infant.
<h3>What is failure to thrive?</h3>
A child is said to suffer from failure to thrive when the child is unable to gain weight in a manner tat is commensurate with those of his mates of the same age or sex.
If a child has been diagnosed as having failure to thrive then the nurse should use half-strength formula when feeding the infant.
Learn more about failure to thrive:brainly.com/question/4529934
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Answer:
100kcal
Explanation:
The law in energy transfer in the food chain is that only 10% of total energy is transferred.
The food chain between the plankton and starfish follows;
Plankton - Mussels and Oysters - Starfishes - Manta Ray
Plankton being the producer produces 100,000kcal
Mussels/Oysters get 10% of 100,000kcal= 10,000kcal.
Starfish gets 10% of 10,000kcal = 1,000kcal
Manta Ray being the final consumer of starfish gets 10% of 1,000kcal = 100kcal