The statement which is true is the slopes are all positive in quadrant I.
Given the differential equation is dy/dx=2x-2y
A differential equation is an equation that contains at least one derivative of an unknown function, either a normal differential equation or a partial differential equation.
Given dy/dx=2x-2y
now slope=2x-2y
Along x-axis, y=0.
So, slope=2x≠0.
Since it depends upon x hence the slope along the y-axis are not horizontal.
Along y-axis, x=0.
So, slope=-2y≠0.
Since the slope along the x-axis are also not horizontal.
In quadrant I
x,y≥0
So, dy/dx≥0
Hence the slopes are all positive in quadrant I.
In quadrant IV,
x≥0,y≤0
so, dy/dx is not always positive.
This, the slope are not all positive in quadrant IV.
Hence, the slope are all positive in quadrant I for the differential equation dy/dx=2x-2y.
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