Maximum Area = 100 m^2
In dealing with maxima and minima, we have to be familiar of the commonly used properties. In this case, if asked about the maximum area of rectangle given with the perimeter, the shape to be considered should be a square. A square is also a king of rectangle.
Perimeter = 40 m
Measure of each side of the square = 40/4
= 10m
Area of the square (maximum area of a rectangle) = 10*10
= 100 m^2
Answer:
38
Step-by-step explanation:
3×5×6 - 52
do GEMDAS Groupings, Exponents, Multiplication, Division, Addition, Subtraction.
multiplication comes first in this proble so you start with that. then you subtract 52
Step-by-step explanation:
A=2πrh+2πr2 ans for 1 one
Answer:
<h2><em> -12y² + 72y</em></h2>
Step-by-step explanation:
Use the distributive property: <em>a(b + c) = ab + ac</em>
<em>-12y(y - 6) = (-12y)(y) + (-12y)(-6) = -12y² + 72y</em>
Answer:
Below in bold
Step-by-step explanation:
∫ dx / (x^2√(9-x^2))
Substitute x = 3sinu and dx = 3cosu du
then the √(9-x^2) = √( 9 - 9sin^2u) = 3 cos u and u = arcsin(x/3)
= 3 ∫(csc^2 u du )/ 27
= 1/9 ∫(csc^2 u du
= -1/9 cot u
= -√9-x^2) / 9x.
