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Kaylis [27]
2 years ago
10

What is the equation of the line described below written in slope-iWhat is the equation of the line described below written in s

lope-intercept form?
the line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0
Mathematics
1 answer:
horsena [70]2 years ago
4 0

The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1

<h3>Equation of a line</h3>

A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;

y - y1 = -1/m(x-x1)

where

m is the slope

(x1, y1) is the intercept

Given the following

Point = (4, -1)

Line: 2x-y - 7 = 0


Determine the slope

-y = -2x + 7

y= 2x - 7

Slope = 2

Substitute

y+1 = -1/2(x -4)

Write in slope-intercept form

2(y + 1) = -(x - 4)

2y+2 = -x + 4

2y = -x + 2

y = -1/2 + 1

Hence the equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1

Learn more on equation of a line here: brainly.com/question/13763238

#SPJ1

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Answer:

h(x) = x - 2

Step-by-step explanation:

h(x) = x - 2

6 0
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A rectangular container can hold 45 candles, while a cylindrical container holds 41 candles. Each rectangular
kap26 [50]

Answer:

  a) no

  b) 143 rectangular containers

  c) 157 cylindrical containers

  d) both (preferring rectangular for the bulk of an order)

Step-by-step explanation:

a) If the company needs to package 6,400 candles, should it use only rectangular or only cylindrical containers to minimize costs?

  No.*

For packaging 41 candles or fewer, the cylindrical container costs less than the rectangular one.

For packaging 6400 candles, there will be 10 candles left over if rectangular containers are used for most of the packaging needs. A dollar can be saved by packaging these remaining candles in a cylindrical container.

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b) How many rectangular containers will be necessary to package 6,400 candles?

  6400/45 = 142 10/45

If rectangular containers are used for all, then 143 are needed.

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c) How many cylindrical containers will be necessary to package 6,400 candles?

  6400/41 = 156 4/41

If cylindrical containers are used for all, the 157 are needed.

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d) Which container should the company use to minimize costs?

  The cost of 143 rectangular containers is 143×$16 = $2288

  The cost of 157 cylindrical containers is 157×$15 = $2355

  The cost of 142 rectangular and 1 cylindrical container is $2287

If only one shape container is used, the company should use rectangular containers to minimize cost. If either shape can be used, cost will be minimized by using one cylindrical container for the remnant of the order.

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* This question is directed solely at the cost of materials required for packaging. We have advocated that both rectangular and cylindrical containers be made available. As a practical matter, the cost to the company of maintaining inventory of both sizes of containers may exceed the savings associated with using a cheaper container for smaller orders.

8 0
3 years ago
A company manufactures two different sizes of boat lifts. The smaller lift requires 1 hour in the welding department and 2 hours
qaws [65]

Answer:

  • The solution that optimizes the profit is producing 0 small lifts and 50 large lifts.
  • Below are all the steps explained in detail.
  • The graph is attached.

Explanation:

<u />

<u>1. Name the variables:</u>

  • x: number of smaller lifts
  • y: number of larger lifts

<u></u>

<u>2.  Build a table to determine the number of hours each lift requires from each department:</u>

<u></u>

Number of hours

                                        small lift    large lift   total per department

Welding department            1x             3y                x + 3y

Packaging department        2x             1y                2x + y

<u></u>

<u>3. Constraints</u>

  • 150 hours available in welding:         x + 3y ≤ 150
  • 120 hours available in packaging:   2x + y ≤ 120
  • The variables cannot be negative:    x ≥ 0, and y ≥ 0

Then you must:

  • draw the lines and regions defined by each constraint
  • determine the region of solution that satisfies all the constraints
  • determine the vertices of the solution region
  • test the profit function for each of the vertices. The vertex that gives the greatest profit is the solution (the number of each tupe that should be produced to maximize profits)

<u></u>

<u>4. Graph</u>

See the graph attached.

Here is how you draw it.

  • x + 3y ≤ 150
  • draw the line x + 3y = 150 (a solid line because it is included in the solution set)
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  • 2x + y ≤ 120
  • draw the line 2x + y ≤ 120 (a solid line because it is included in the solution set)
  • shade the region below and to the left of the line

  • x ≥ 0 and y ≥ 0: means that only the first quadrant is considered

  • the solution region is the intersection of the regions described above.

  • take the points that are vertices inside the solutoin region.

<u>5. Test the profit function for each vertex</u>

The profit function is P(x,y) = 25x + 90y

The vertices shown in the graph are:

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  • (42,36)
  • (60,0)

The profits with the vertices are:

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  • P(60,0) = 25(60) + 90(0) = 1,500

Thus, the solution that optimizes the profit is producing 0 smaller lifts and 90 larger lifts.

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11 pints = 22 cups
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3 0
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Brrunno [24]
The sequence is arithmetic since the common difference that is equal
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