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bija089 [108]
3 years ago
10

Is 0.393939 irrational

Mathematics
2 answers:
amm18123 years ago
5 0

Answer:

yes

Step-by-step explanation:

because it is repeating desimal

skelet666 [1.2K]3 years ago
4 0
Yes because it is a repeating decimal
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10. Amina is currently twice as old as her younger brother,
maks197457 [2]

Answer:

When Amina is 18. Saad would be;

k. 14

Step-by-step explanation:

Let "x" represent Anita's current age and let "y" represent Saad's current age, we have;

Anita's age = 2 × Saad's age

Therefore;

x = 2 × y...(1)

In 4 years, we will get;

x + 4  = 1.5 × (y + 4)...(2)

Substituting the value of x in equation (1) into equation (2), we get;

2·y + 4 = 1.5·y + 1.5 × 4 = 1.5·y + 6

2·y + 4 = 1.5·y + 6

2·y - 1.5·y   = 6 - 4 = 2

0.5·y = 2

y = 2/0.5 = 4

Saad's current age = y = 4 years

From equation (1), we have;

x = 2 × y = 2 × 4 = 8

Amina's current age = x = 8 years

When Amina is 18, we have;

18 = 10 + 8 = 10 + x

Therefore, Amina would be 18 in 10 years time from now, from which we have;

Saad would be 10 years + y = 10 years + 4 years = 14 years in 10 years from now

Therefore, when Amina would be 18 years in 10 years from now Saad would be 14 years.

6 0
3 years ago
13. 92÷3 need to know estimation and show work
V125BC [204]

Answer:

30.667

Step-by-step explanation:

92 divided by 3 is 30.667

92/3=30.667

6 0
1 year ago
Read 2 more answers
What is -9(4f-6f)+(-15f)<br><br> I need the answer ASAP
SIZIF [17.4K]
The answer is 3f
<span>=<span><span>18f</span>+<span>−<span>15f</span></span></span></span><span>=<span>(<span><span>18f</span>+<span>−<span>15f</span></span></span>)</span></span><span>=<span>3<span>f</span></span></span>
4 0
4 years ago
Read 2 more answers
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
4 years ago
You live 3 1/2 miles away from school. In the morning, you walk 1/4 mile directly toward school to take the bus. You walk home s
Tresset [83]
6 and a half miles......
6 0
3 years ago
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