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bija089 [108]
3 years ago
10

Is 0.393939 irrational

Mathematics
2 answers:
amm18123 years ago
5 0

Answer:

yes

Step-by-step explanation:

because it is repeating desimal

skelet666 [1.2K]3 years ago
4 0
Yes because it is a repeating decimal
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The entrance hall in Black's family house has a perimeter of 71 2/3 ft.IF it is 9 2/5 ft wide, how long is it?
serious [3.7K]

Answer: 26 13/30 feet

Step-by-step explanation:

The hall is in the shape of a rectangle. The perimeter of a rectangle is:

= 2(length + width)

= 2l + 2w

Since perimeter = 71 2/3 ft and Width = 9 2/5 ft wide, the length will be calculated thus:

Perimeter = 2l + 2w

71⅔ = 2l + 2(9 2/5)

71 2/3 = 2l + (2 × 47/5)

71 2/3 = 2l + 94/5

71 2/3 = 2l + 18 4/5

Collect like terms

2l = 71 2/3 - 18 4/5

2l = 71 10/15 - 18 12/15

2l = 52 13/15

l = (52 13/15 ÷ 2)

l = 793/15 × 1/2

l = 793/30

l = 26 13/30

Therefore, the length is 26 13/30ft

3 0
3 years ago
The first 5 numbers of a sequence are shown below. Which of the following functions produces the sequence with n: (1, 2, ...,
Rasek [7]

Answer:

C)

Step-by-step explanation:

f(n) = 26 + 9(n-1)

4 0
3 years ago
If the area around the vegetable garden is of uniform width (labeled with x) and the dimensions of the vegetable garden is 45 fe
Nady [450]
Area of Rectangle = Width × Length

Vegetable Garden
Width = 20
Length = 45
Area of Vegetable Garden = 20×45=900 Sq ft

Area of Entire Garden = Width × Length
Width = 20 + 2x
Length = 45 + 2x
Area = (20 + 2x)(45 + 2x)
(2x + 20)(2x + 45)
4x^2 + 90x + 45x + 900
Area of Entire Garden = 4x^2 + 135x + 900

Area of Flower Garden = Area of Entire Garden - Area of Vegetable Garden

(4x^2 + 135x + 900) - (20 × 45)
4x^2 + 135x + 900 - 900
Area of Flower Garden = 4x^2 + 135x

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Step-by-step explanation:

6 0
2 years ago
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Step-by-step explanation:

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