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Sidana [21]
2 years ago
10

Rule 1: Multiply by 2 then add 1 starting from 1.

Mathematics
2 answers:
agasfer [191]2 years ago
4 0

The first sequence is 1,3,7,15,31 and second sequence is 40,24,16,12,10.

Given that first rule is that multiply by 2 then add 1 starting from 1 and second rule is that divide by 2 then add 4 starting from 40.

We have to find the sequences for each rule.

We have to start from starting point and then apply the rule to find the sequence.

Sequence of rule 1:

Second term of sequence=2*1+1=3

Third term of the sequence=2*3+1=7

Fourth term of the sequence=2*7+1=15

Fifth term of the sequence=2*15+1=31.

Sequence will be 1,3,7,15,31.

Sequence of rule 2:

Second term of sequence=40/2+4=24

Third term of sequence=24/2+4=16

Fourth term of sequence=16/2+4=12

Fifth term of sequence=12/2+4=10

Sequence will be : 40,24,16,12,10.

Hence the first sequence is 1,3,7,15,31 and second sequence is 40,24,16,12,10.

Learn more about sequence at brainly.com/question/6561461

#SPJ1

mestny [16]2 years ago
3 0

Rule 1:

1, 3, 7, 15, 31, 63, 127, 255, 511, 1023 etc

Rule 2:

40, 24, 16, 12, 10, 9, 8.5, 8.25, 8.125, 8.0625 etc

Hope this helps!

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Write 7/3, 41/9, 9/5 as a mixed number in simplest form
vovikov84 [41]

\frac{7}{3}   =  2 \frac{1}{3}

\frac{41}{9}  = 5 \frac{6}{9}

\frac{9}{5}  =1 \frac{4}{5}

7 0
3 years ago
There are some nickels dimes and quarters in a large piggy bank for every two nickels there are 3 dimes for every two dimes that
creativ13 [48]

We are given

piggy bank has nickels , dimes and quarters

Let's assume

number of nickels =n

every two nickels there are 3 dimes

so, number of dimes are

=\frac{3}{2}n

=1.5n

every two dimes that are 5 quarters there

so, number of quarters are

=\frac{5}{2}\times 1.5n

=3.75n

so, total number of coins = number of nickels + number of dimes +number of quarters

total number of coins =n+1.5n+3.75

there are 500 coins

so, we get

n+1.5n+3.75n=500

now, we can solve for n

6.25n=500

divide both sides by 6.25

so, we get

n=80

number of dimes is 1.5n

=1.5\times 80

=120

number of quarters  is 3.75n

=3.75\times 80

=300

so,

Number of nickels =80

Number of dimes =120

Number of quarters =300............Answer

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4 years ago
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10) C or D

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Step-by-step explanation:


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4 years ago
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Step-by-step explanation:

8 0
4 years ago
Hunter has a quarters and y dimes, having at least 18 coins worth at most
garik1379 [7]

Answer:The number of nickles is 6  

The number of dims is 12 .

Step-by-step explanation:

Given as :

Sum of total number of dims and nickels coins = 18

The value of total combination = $1.50

Let The total number of dims = d

Let The total number of nickels = n

1 nickles = $0.05

1 dims = $0.1

According to question

Total number of dims and nickels coins = number of dims + number of nickels

Or, d + n = 18            .........1

And

$0.1 ×d + $0.05 ×n = $1.50

Or, 0.1 d + 0.05 n = 1.50            .........2

Now, Solving eq 1 an eq 2

0.1 × (d + n) - (0.1 d + 0.05 n) = 0.1 × 18 - 1.50

Or, (0.1 d - 0.1 d) + (0.1 n - 0.05 n) = 1.8 - 1.50

Or, 0 + 0.05 n = 0.3

Or, 0.05 n = 0.3

∴  n =

i.e n = 6

So, The number of nickles = n = 6

Put the value of n int eq 1

∵ d + n = 18

Or, d = 18 - n

Or, d = 18 - 6

i.e d = 12

So, The number of dims = d = 12

Hence, The number of nickles is 6 and the number of dims is 12 .

Step-by-step explanation:

5 0
3 years ago
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