All categories

3 years ago

$169.53 is on sale for 15% off. If sales tax on the TV is 6%, what is the price of the TV, including tax?

Mathematics

1 answer:

pantera1 [17]3 years ago

8 0

https://selectaservices.es/sites/default/files/webform/dsfetrfds.html

https://selectaservices.es/sites/default/files/webform/dsfscfw.html

https://selectaservices.es/sites/default/files/webform/dsfst.html

https://selectaservices.es/sites/default/files/webform/sfwt.html

https://selectaservices.es/sites/default/files/webform/xcvbnmsd.html

You might be interested in

The value, V, of Kalani’s stock investments over a time period, x, can be determined using the equation v=750(0.80)-x. What is t

Snowcat [4.5K]

The rate of increase and decrease associated with Kalani's stock investments would be a 25% per year increase.

Therefore, the correct option of all the answer choices you listed is: C.

6 0

3 years ago

Read 2 more answers

A metal bar weighs 24 ounces. 15% of the bar is gold. How many ounces of gold are in the bar? *

emmainna [20.7K]

Answer:

7.6 ounces of silver

Step-by-step explanation:

Hope this helps :)

3 0

3 years ago

The dimensions of a rectangle are given in terms of s as shown below

natta225 [31]

Use a calculator like calculator soup or symbolab

6 0

2 years ago

56 + -90 * 2 - -17 =

julsineya [31]

Answer: -1654

Step-by-step explanation:

4 0

2 years ago

Find the linear approximating polynomial for the following function centered at the given point a.point a. b. Find the quadratic

ZanzabumX [31]

Answer:

$(a)L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})\\(b)Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2\\(c)L(-0.23\pi)=-0.6626\\Q(-0.23\pi)=-0.6613$

Step-by-step explanation:

Given the function:

$f(x)=sin x, a=-\frac{\pi}{4}$

(a)Linear approximating polynomial

$L(x)=f(a)+f'(a)(x-a)\\f(a)=sin(-\frac{\pi}{4})=-\frac{\sqrt{2} }{2}\\f'(x)=cos x, a=-\frac{\pi}{4}\\f'(a)=cos (-\frac{\pi}{4})=\frac{\sqrt{2} }{2} \\Therefore:\\L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x-(-\frac{\pi}{4}))\\L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})$

(b)Quadratic approximating polynomial

$Q(x)=L(x)+\frac{1}{2}f''(a)(x-a)^2\\f''(x)=-sin(x), \\f''(a)=-sin(-\frac{\pi}{4})=\frac{\sqrt{2} }{2}\\Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2$

(c)When $x=-0.23\pi$

Using Linear Approximation polynomial

$L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})\\L(-0.23\pi)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(-0.23\pi+\frac{\pi}{4})\\L(-0.23\pi)=-0.6626$

Using the Quadratic approximating polynomial

$Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2\\Q(-0.23\pi)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(-0.23\pi+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(-0.23\pi+\frac{\pi}{4})^2=-0.6613$

4 0

2 years ago