Answer:

Step-by-step explanation:
We are given:

Factor:

Difference of Two Squares:

Zero Product Property:

Solve:

Take the square root. Since we are taking an even-root, it requires plus/minus:

Answer:
A,C,D,E
Step-by-step explanation:
Bc I guessed and got it right
Answer:
Answer
Step-by-step explanation:
(a) B ⊄ A (b) C ⊂ A (c) B ⊄ C (d) ∅ ⊂ B (empty set is an element of any set)
(e) C ⊂ C (reflexitivity).
The equation is at the top, the steps are in between, and the answer is at the bottom
hope this helps
Answer:
<em>The correct option is: 11.5</em>
Step-by-step explanation:
Suppose, the length of the unknown side is 
So, here the length of hypotenuse is 14 and the lengths of other two sides are 8 and
.
As the given triangle is right angle triangle, so <u>using Pythagorean theorem</u>, we will get.........

<em>(Rounded to the nearest tenth)</em>
So, the length of the unknown side is 11.5