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First of all, when I do all the math on this, I get the coordinates for the max point to be (1/3, 14/27). But anyway, we need to find the derivative to see where those values fall in a table of intervals where the function is increasing or decreasing. The first derivative of the function is 
. Set the derivative equal to 0 and factor to find the critical numbers. 
, so x = -3 and x = 1/3. We set up a table of intervals using those critical numbers, test a value within each interval, and the resulting sign, positive or negative, tells us where the function is increasing or decreasing. From there we will look at our points to determine which fall into the "decreasing" category. Our intervals will be -∞<x<-3, -3<x<1/3, 1/3<x<∞. In the first interval test -4. f'(-4)=-13; therefore, the function is decreasing on this interval. In the second interval test 0. f'(0)=3; therefore, the function is increasing on this interval. In the third interval test 1. f'(1)=-8; therefore, the function is decreasing on this interval. In order to determine where our points in question fall, look to the x value. The ones that fall into the "decreasing" category are (2, -18), (1, -2), and (-4, -12). The point (-3, -18) is already a min value.
Answer:
D
Step-by-step explanation:
Use the exponents to guide your answer. When we examine -∞, if the exponent is even, it will be a positive value. If it is odd, it will be a negative value. For positive ∞, it doesn't matter whether odd or even, the value will be positive.
So we automatically know as x approaches ∞, y has to be ∞.
But for -∞ it is trickier. You have 3x^6 and 75x^4 together that is positive, and 30x^5 that is negative. The first two is greater than 30x^5 overall, so as x approaches -∞, y also approaches ∞.
If you need a visual, this is what it looks like:
Answer:
<h2>A. {x | x = –5, –3, 1, 2, 6}</h2>Step-by-step explanation:
<em>The mapping between sets is shown in the image attached.</em>
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Remember that the Input Set represents the domain, the x-values. The Output Set represents the range, the y-values.
So, basically we need to choose the set of x-values which has the same elements than the Input Set showed in the image.
Therefore, the right answer is A, because it has the same elements than the Input Set shown.
