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1 year ago

Select the correct answer from the drop-down menu.

Mathematics

1 answer:

Lilit [14]1 year ago

5 0

The C is perpendicular to AB

When using paper, the paper perpendicular te construct to is folded so that AB is divided equally and the two sides of. line AB will lie exactly on top of each other.

When using a reflective device to construct a live perpendicular to line AB, set One end of the device to coincide with point C, and then swing the other end of the device so that the reflection of line AB coincides with the midpoint of AB

The question is incomplete hence the complete question is shown here

Select the correct answer from the drop-down menu. Compare the steps for constructing a perpendicular line to line through point using a reflective device and using paper. , When using paper to construct the perpendicular line, the paper is folded so that and the two sides of line will lie exactly on top of each other. When using a reflective dewice to construct a line perpendicular to line , set one end of the device to coincide with , and then swing the other end of the device so the reflection of line coincides with.

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a pole that is 3m tall casts a shadow that is 1.72m long. at the same time, a nearby building casts a show that is 50.5 m long.

Veronika [31]

Answer:

88.08 m tall

Step-by-step explanation:

Pole:

tall/long
3/1.72

Building:

tall/long

x/50.5

Solve for x:

3/1.72 = x/50.5

1.72x = 151.5

x ≈ 88.08

8 0

2 years ago

Solve the equation x to the second power - 13x to the third power + 47x -35=0 given that 1 is a zero of f(x) = x to the third po

zloy xaker [14]

Answer:

The solution sets are 1, 5 and 7

Step-by-step explanation:

Given the polynomial function,

f(x) = x³-13x²+47x-35

If 1 is a zero function of f(x), according to factor theorem, the linear equation x-1 is a factor of the polynomial.

To get the other solution set, we will have to divide the polynomial function by x-1 and factorize the quotient function.

Factorising the resulting quotient function.

Q(x) = x²-12x+35 = 0

= x²-5x-7x+35 = 0

= x(x-5)-7(x-5) = 0

(x-5)(x-7) = 0

x-5 = 0 and x-7 = 0

x = 5 and 7

6 0

3 years ago

I need the answers please help

Andrej [43]

Answer:

For the first one: 2+3(1) = 5

Second one: 5=5

Third one: 1 = -2 + 3

Last one: 1=1

Step-by-step explanation:

4 0

3 years ago

What inequalities have the solution set graphed in the number line? Select two options.

Akimi4 [234]

The answer should be 1 and three

7 0

3 years ago

Find the first 4 terms in each sequence

koban [17]

Answer:

a₁ = -21 (Given)

a₂ = -28

a₃ = -35

a₄ = -42

Step-by-step explanation:

First term a₁ = -21 (Given)

…………………………………

Second term a₂ :

a₂ = $a_{2-1} - 7\\a_{1} - 7\\a_{1} = -21\\-21 - 7 = -28$

…………………………………

Third term a₃ :

a₃ = $a_{3-1} - 7\\a_{2} - 7\\a_{2} = -28\\-28 - 7 = -35$

…………………………………

Fourth term a₄ :

a₄ = $a_{4-1} - 7\\a_{3} - 7\\a_{3} = -35\\-35 - 7 = -42$

5 0

2 years ago