Answer:
see graph
Step-by-step explanation:
g(x) = 3^ x .
h(x) = 2^-x
We want to subtract them
f(x) = 3^x - 2^(-x)
I will rewrite without the negative exponent
f(x) = 3^x - (1/2)^(x)
Lets pick a couple of points
f(0) = 3^0 - (1/2) ^ 0 = 1-1 = 0
As x gets large 3^x gets large and 1/2^x gets close to 0, so it will get large
As x goes to negative infinity, 3^x goes to zero and 1/2^ gets large so we get - infinitity
