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dmitriy555 [2]
3 years ago
10

Solve for x and show work 10x + 80 < y = 20x​

Mathematics
1 answer:
julsineya [31]3 years ago
6 0

Answer:

x=8

Step-by-step explanation:

10x + 80 < y = 20x

subtract 80 from both sides

10x = 20x - 80

subtract 20 from both sides

-10x = -80

divide both sides by -10

8

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Answer:

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Step-by-step explanation:

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3 years ago
Solve for x! 37m,12m,5xm
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Answer:

\Huge\boxed{x=7}

Step-by-step explanation:

Hello there!

The first thing we want to do is find the measure of the large leg

To do so we use the Pythagorean theorem which says a^2+b^2=c^2\\

where a and b are legs and c is the hypotenuse

we want to find b given the hypotenuse and short leg

so  b^2=c^2-a^2

all we have to do is plug in a ( a = short leg so a would equal 12) and c ( c = hypotenuse so c would equal 37)

so

b^2=37^2-12^2\\37^2=1369\\12^2=144\\1369-144=1225\\b^2=1225\\\sqrt{b^2} =b\\\sqrt{1225} =35\\b=35

so the longer leg is equal to 35

35=5x

divide each side by 5

5x/5=x

35/5=7

we're left with x=7

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