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tamaranim1 [39]
2 years ago
9

po3 Smith is eligible to take the po2 advancement exam the only evaluation he received his current pay greater than Frost evalua

tion
SAT
1 answer:
andreev551 [17]2 years ago
5 0

In the case above, Smith  does not need anything, or nothing is required to occur to establish a PMA.

<h3>What is an advancement exam?</h3>

An advancement exam is known to be one that gives an unbiased factor in regards to the Final Multiple Score (FMS) algorithm and it is said to help in the rank order of qualified candidates in terms of  advancement consideration.

Hence, In the case above, Smith  does not need anything, or nothing is required to occur to establish a PMA.

See full question below

po3 Smith is elligible to take the po2 advancement exam. The only evaluation he received in his current paygrade is a frocked evaluation. what, if anything, is required to occur to establish a pma.

Learn more about PMA from

brainly.com/question/12144816

#SPJ1

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In triangle ABC, the measure of ∠B is 90°, BC=16, and AC=20. Triangle DEF is similar to triangle ABC, where vertices D, E, and F
Andreas93 [3]
  • AC=Hypotenuse=20
  • BC=Base=16

AB:-

Apply Pythagorean theorem

\\ \rm\rightarrowtail P^2=H^2-B^2

\\ \rm\rightarrowtail P^2=20^2-16^2

\\ \rm\rightarrowtail P^2=400-256

\\ \rm\rightarrowtail P^2=144

\\ \rm\rightarrowtail AB=12

Now

  • DE=AB/3=12/3=4
  • EF=BC/3=16/3=5.3
  • DF=AC/3=20/3=6.6

Now

\\ \rm\rightarrowtail sinF=\dfrac{DE}{DF}

\\ \rm\rightarrowtail sinF=\dfrac{4}{6.6}

\\ \rm\rightarrowtail sinF=0.61

4 0
2 years ago
At a large corporation, the distribution of years of employment for the employees has mean 20.6 years and standard deviation 5.3
Cerrena [4.2K]

Answer:

Yes

Explanation:

The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma}\\\\where\  \mu=mean.\sigma=standard\ deviation,  x=raw\ score.\\\\For\ a \ sample\ size\ n:\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }

For a normal distribution with a mean of μ and standard deviation σ, For any sample size (n) drawn from this population, the sample mean is normally distributed, with mean \mu_x=\mu and standard deviation \sigma_x=\frac{\sigma}{\sqrt{n } } \\\\.

Hence given that a mean of μ = 20.6 years and standard deviation σ = 5.3 years, for a sample size of 100:

mean \mu_x=\mu=20.6\ years and standard deviation \sigma_x=\frac{\sigma}{\sqrt{n } } =\frac{5.3}{\sqrt{100} }=0.53\ years \\\\.

7 0
3 years ago
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How do lines 1 through 12 mainly contribute to the poem ""sybil ludington’s ride""?
natka813 [3]

Answer:

A

Explanation:

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2 years ago
Which of the following represents
Serhud [2]

Answer:

x=3

Explanation:

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