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We are looking for the value of the second integer, so let's mark it as X.
Then three consecutive integers are : (x-1) , x , (x+1)
The sum of the first and the third integers (X-1) + (X+1)
Five less than three times the second integer 3X - 5
Now we can write an equation and solve it for X
(X-1)+(X+1)= 3X - 5 simplifying left part
2X = 3X -5 subtract 2X from both sides
0 = X-5
X=5
SO THREE CONSECUTIVE INTEGERS ARE 4, 5, 6
Answer:
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Explanation:
