<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D" id="TexFormula1" title="\sqrt{x}" alt="\sqrt{x}" align="absmiddle" class="late

All categories

Dmitriy789 [7]

2 years ago

x-formula"> $\sqrt{x}$ 4- $\sqrt{x}$ $\sqrt{x}$ 7 - $\sqrt{x}$ $\sqrt{x}$ 4+ $\sqrt{x}$ 7 + $\sqrt{x}$ 2

Mathematics

1 answer:

LiRa [457]2 years ago

5 0

$4x - 7x - 4x + 7 \sqrt{x} + \sqrt{x}$

$- 7x + 8 \sqrt{x}$

You might be interested in

(13) The Modern Grocery has cashews that sell for $5.00 a pound and peanuts that sell

bazaltina [42]

Answer:

solution:

x = pounds of cashews = 20

y = pounds of peanuts = 70

Step-by-step explanation:

x = pounds of cashews

y = pounds of peanuts

---

4.75x + 2.50y = 3.00*90

x + y = 90

---

put the system of linear equations into standard form

---

4.75x + 2.50y = 270

x + y = 90

5 0

3 years ago

I REALLY NEED HELP TO PASS!

expeople1 [14]

A = 1

4/17=2/8.5
...................

7 0

3 years ago

Read 2 more answers

Please help me need help need help

Minchanka [31]

Answer:

See attachment for answers

Step-by-step explanation:

4 0

3 years ago

Find the average rate of change of a function that contains the points (-2,3) and (2,5). -2, -1/2, 1/2, 2

UkoKoshka [18]

Answer:

The answer is " $\frac{1}{2}$ ".

Step-by-step explanation:

Given points:

$(-2,3)\\\\(2,5)\\\\$

average rate=?

$x_1=-2\\\\y_1=3\\\\x_2=2\\\\y_2=5$

$average\ rate=\frac{y_2-y_1}{x_2-x_1}$

$=\frac{5-3}{2-(-2)}\\\\=\frac{5-3}{2+2}\\\\=\frac{2}{4}\\\\=\frac{1}{2}$

5 0

3 years ago

What’s the answer??(SOMEONE PLEASE HELP ME)

Evgesh-ka [11]

To find $f^{-1}$ , you can switch the "x" and "f(x) or y" in the equation.

$f(x) = \sqrt[3]{x-2} +8$

$y = \sqrt[3]{x-2}+ 8$

$x = \sqrt[3]{y-2}+8$

Now you need to isolate the "y"

$x = \sqrt[3]{y-2}+8$ Subtract 8 on both sides

$x - 8 = \sqrt[3]{y-2}$ Cube ( ³ ) each side to get rid of the ∛

$(x-8)^{3} = (\sqrt[3]{y-2}) ^{3}$

$(x-8)^{3} = y -2$ Add 2 on both sides

$(x-8)^{3}+2 = y$

$f^{-1} = (x-8)^{3} + 2$

5 0

3 years ago

Read 2 more answers