Help me answer 49, ignore number 50 please.

Mathematics

2 answers:

Alika [10]3 years ago

7 0

A that’s the answers

ryzh [129]3 years ago

5 0

you solve it like an equation.

4x+20<40

4x<20

x<5

so the answer would be anything less than 5, which is A

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Jeez math help please!!!!!

viva [34]

(3y^7)^3 3^3*y^(7*3)
------------ = ------------------
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(3y^7)^3 3^3*y^(7*3) 27*y^21 (mult. together the exponents 3 and 7)
------------ = ------------------ = --------------
9y^9 9*y^9 9*y^9

That 27/9 reduces to 3. y^(21) / y^9 reduces to y^12.

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