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Nookie1986 [14]
2 years ago
10

Mr. smith leaves 3 hours before mrs smith. if he averages 55mph and she 65mph how many hours will it take mrs smith to catch up

Mathematics
1 answer:
motikmotik2 years ago
3 0

It will take 16hr 30min for Mrs. Smith to catch up.

<h3>To find how many hours will it take Mrs smith to catch up:</h3>

Let,

t + 3 = Time of Mr. Smith

t = Time of Mrs. Smith

v1 = 55 mph the speed of Mr. Smith

v2 = 65 mph the speed of Mrs. Smith

Formula: Distance = speed × time

v1 ( t + 3)  = v2t

55 ( t + 3 ) = 65t

65t = 55t + 165

65t - 55t = 165

10t = 165

t = 16.5 hr

t = 16 hr 0.5 × 60 min

t = 16 hr 30 min

Therefore, it will take 16hr 30min for Mrs. Smith to catch up.

Know more about distance here:

brainly.com/question/17273444

#SPJ4

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QUESTION 17 PLEASE HELP ME ASAPP
Butoxors [25]
Answer: change over time
Explanation: it is decreasing in height therefore is decreasing in altitude
4 0
2 years ago
Read 2 more answers
How much interest is earned on a principal of $316 invested at an interest rate of 9%
anzhelika [568]

Answer:

$130.06

Step-by-step explanation:

Interest is calculated as shown;

I = A - P

A is the amount

P is the principal

Given

Principal = $316

Rate R = 9% = 0.09

Time t = 4yrs

Substiutte and get Amount A

A  =P(1+r)^n

A = 316 (1+0.09)^4

A = 316(1.09)^4

A = 316(1.4116)

A = 446.06

Interest = 446.06 - 316

Interest = 130.06

Hence the interest is $130.06

4 0
3 years ago
$15,074 is invested, part at 14% and the rest at 5%. If the interest earned from the amount invested at 14% exceeds the interest
Flauer [41]

The rate at 14% and 5% are $12, 883 and $2191 respectively.

<h3>How to determine the rate</h3>

Given that;

Invested amount = $ 15, 074 at 14% and 5%

Let rate at 14% = x

rate at 5% = y

We have rate at 9% exceeds that of 5% by $1694. 07

Hence,

0. 14x = 0. 05y + $1694. 07 ⇒ equation 1

x + y = $15, 074 ⇒ equation 2

Make 'x' the subject

x = 15, 074 - y

Substitute in equation 2

0. 14(15, 074 - y) = 0. 05y + $1694. 07

Expand the expression

2, 110. 36 - 0. 14y = 0.05y + 1694. 07

Collect like terms

416. 29 = 0. 19y

Make 'y' the subject

y = \frac{416. 29}{0. 19}

y = $2, 191

Substitute the value in equation 2

x + y = $15, 074

x = $15, 074 - y

x = $15, 074 - 2191

x = $12, 883

Therefore , the rate at 14% and 5% are $12, 883 and $2191 respectively.

Learn more about simultaneous equations here:

brainly.com/question/16863577

#SPJ1

4 0
1 year ago
Please help I need an answer please
erma4kov [3.2K]
15 girls 12 boys 5x3=15 and 4x3=12 so 15 girls 12 boys
3 0
3 years ago
Please Help Me
ludmilkaskok [199]

Given:

The point (9,-12) is on terminal side of angle theta in standard position.

To find:

The exact value of each of the six trigonometric functions of theta.

Solution:

The given point is (9,-12). Here, x-coordinate is positive and y-coordinate is negative. So, the point lies in 4th quadrant and only cos and sec are positive in 4th quadrant.

We know that,

r=\sqrt{x^2+y^2}

r=\sqrt{9^2+(-12)^2}

r=\sqrt{81+144}

r=\sqrt{225}

r=15

Now,

\sin \theta=\dfrac{y}{r}=\dfrac{-12}{15}=-\dfrac{4}{5}

\cos \theta=\dfrac{x}{r}=\dfrac{9}{15}=\dfrac{3}{5}

\tan \theta=\dfrac{y}{x}=\dfrac{-12}{9}=-\dfrac{4}{3}

\cot \theta=\dfrac{1}{\tan \theta}=-\dfrac{3}{4}

\text{cosec} \theta=\dfrac{1}{\sin \theta}=-\dfrac{5}{4}

\sec \theta=\dfrac{1}{\cos \theta}=\dfrac{5}{3}

Therefore, the values of six trigonometric functions of theta are \sin \theta=-\dfrac{4}{5},\cos \theta=\dfrac{3}{5},\tan \theta=-\dfrac{4}{3},\cot \theta=-\dfrac{3}{4},\text{cosec} \theta=-\dfrac{5}{4},\sec \theta=\dfrac{5}{3}.

6 0
3 years ago
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