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Nookie1986 [14]
2 years ago
10

Mr. smith leaves 3 hours before mrs smith. if he averages 55mph and she 65mph how many hours will it take mrs smith to catch up

Mathematics
1 answer:
motikmotik2 years ago
3 0

It will take 16hr 30min for Mrs. Smith to catch up.

<h3>To find how many hours will it take Mrs smith to catch up:</h3>

Let,

t + 3 = Time of Mr. Smith

t = Time of Mrs. Smith

v1 = 55 mph the speed of Mr. Smith

v2 = 65 mph the speed of Mrs. Smith

Formula: Distance = speed × time

v1 ( t + 3)  = v2t

55 ( t + 3 ) = 65t

65t = 55t + 165

65t - 55t = 165

10t = 165

t = 16.5 hr

t = 16 hr 0.5 × 60 min

t = 16 hr 30 min

Therefore, it will take 16hr 30min for Mrs. Smith to catch up.

Know more about distance here:

brainly.com/question/17273444

#SPJ4

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A sector is a <u>part</u> of a <u>circle</u> that is formed by two<em> radii,</em> and an <em>arc</em>. So that the length of the <em>safety railing</em> required is 31.4 feet.

A sector is a <em>part </em>of a <u>circle</u> that is formed by two <u>radii</u>, and an <u>arc</u>, thus forming a <em>central</em> angle.

Thus the required <em>length</em> of safety railing can be considered as the <u>arc</u> of the<em> sector. </em>

So that;

<u>length</u> of an <u>arc</u> = (θ / 360^{o}) * 2\pir

where θ is the <u>measure</u> of the <em>central angle</em> of the sector, and r is the <u>radius</u> of the sector.

From the given question, θ = 45°, and r = 40 feet.

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<u>length</u> of the<em> safety railing </em>= (45° / 360^{o}) * 2 * 3.14 * 40

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<u>length</u> of <em>safety railing</em> = 31.4

Therefore, the <u>length</u> of the <em>safety railing</em> required is 31.4 feet.

For more clarifications on the length of an arc, visit: brainly.com/question/2005046

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