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GalinKa [24]
3 years ago
11

George is at a trade show and is trading cards. He started the day with 50 cards, traded 5 of his cards for 1 of Billy's cards,

traded 2 of his cards for 7 of Eloise's cards, and then traded 6 of his cards for 6 of Migel's cards. How many cards does he have at the end of the day?
Mathematics
2 answers:
solmaris [256]3 years ago
8 0
50-5+1-2+7-6+6=51 you have to add and subtract the number of cards he had and traded
poizon [28]3 years ago
7 0
51 cards because when he traded with billy he had 46 but then added 7 of eloise's cards he now has 51 and well migel is making an equal trade so by the end of the day he ends up with 51 cards 
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\displaystyle\\Answer:\ K=\frac{5}{9}(F-32^0)+273.15^0

Step-by-step explanation:

\displaystyle\\F=\frac{9}{5} (K-273.15)+32\\F-32=\frac{9}{5} (K-273.15)+32-32\\F-32=\frac{9}{5} (k-273.15)\\Multiply\  both\  parts\  of\  the\  equation\  by\ \frac{5}{9} \\(\frac{5}{9})(F-32)=\frac{9}{5}  (K-273.15)(\frac{5}{9} )\\\\\frac{5}{9} (F-32)=K-273.15\\\\\frac{5}{9} (F-32)+273.15=K-273.15+273.15\\\\\frac{5}{9} (F-32)+273.15=K

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2 years ago
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I actually began with the guess-and-check method, but seeing as that won't always work, let's go over the formal way. To get the original number, you first need to determine how many times the number was squared.

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Step-by-step explanation:

Hope this helps!

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4 years ago
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