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Alex17521 [72]
2 years ago
6

A ball is thrown downward from the top of a 120-foot building with an initial velocity of 20 feet per second. The

Mathematics
1 answer:
Sholpan [36]2 years ago
6 0

Answer:

t=\frac{-5+\sqrt{505}}{8}

Step-by-step explanation:

The ball strikes the ground when h = 0.

-16t^2 - 20t + 120 = 0 \\ \\ 4t^2 + 5t - 30=0 \\ \\ t=\frac{-5 \pm \sqrt{5^{2}-4(4)(-30)}}{4(2)} \\ \\ t=\frac{-5 \pm \sqrt{505}}{8}

However, as time most be positive, we only consider the positive case.

So,

t=\frac{-5+\sqrt{505}}{8}

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