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Leno4ka [110]
3 years ago
14

Plz help due soooon thx

Mathematics
1 answer:
Readme [11.4K]3 years ago
5 0
Is blank dude can’t help you there
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A persons car traveled 60 miles in 45 minutes, how many miles per hour was it traveling?
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To reach 60 miles in 45 minutes you’ll have to drive 80mph
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What is the equation for the line that passes through the point (0,0) and has a slope of -1/2
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Assuming it's a linear equation, y= -1/2x

6 0
3 years ago
Cameron has decided to diversify his investments in the following way $3000 in an account earning 2.7% simple interest $5000 in
jolli1 [7]
A=3000(1+3*0.027)=3,243
Interest earned 243
A=5,000×(1+0.018)^(3)=5,274.89
Interest earned 274.89
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3 0
4 years ago
In 2010, the population of a town was 8500. The population decreased by 4.5% each year.
Soloha48 [4]

Answer:

This is a problem in exponential decay.

a) If a town's population decreases by 4.5% every year that also means that the town's population decreases by a factor of .955 each year.  (1 - .045 = .955)

So, after 5 years, the town's population is:

8,500 * .955^5 which equals 6,752.

So, basically, after t years, the town's population equals

8,500 * .955^t  where t is the number of years that have passed since the year 2010.

b) population = 8,500 * .955 ^ (number of years since 2010)

7,000 / 8,500  = .955 ^ (number of years since 2010)

0.8235294118  = .955 ^ (number of years since 2010)

To solve for (number of years since 2010) we take logs of both sides

log (0.8235294118 ) = number of years since 2010 * log(.955)

-0.0843208857  = number of years since 2010 * -0.0199966284

-0.0843208857  / -0.0199966284  = number of years since 2010

4.2167551422  = number of years since 2010

So, population = 7,000 when the year is 2014.2167551422

Or about  2.6 months into 2014

(YES, it's just that "easy")  LOL

Step-by-step explanation:

6 0
3 years ago
Please help asap! Im timed, Thanks!
blagie [28]
B and D I hope this helped
8 0
3 years ago
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