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Orlov [11]
2 years ago
11

A total of $5000 is invested: part at 7% and the remainder at 12%. How much is invested at each rate if the annual interest is $

400?
Mathematics
1 answer:
atroni [7]2 years ago
3 0

The amount invested in the account that yields 7% interest is $4000.

The amount invested in the account that yields 12% interest is $1000.

<h3>What are the linear equations that represent the question?</h3>

a + b = 5000 equation 1

0.07a + 0.12b = 400 equation 2

Where:

a = amount invested in the account that yields 7% interest.

b =  amount invested in the account that yields 12% interest.

<h3>How much is invested at each rate?</h3>

Multiply equation 1 by 0.07

0.07a + 0.07b = 350 equation 3

Subtract equation 3 from equation 2

0.05b = 50

b = 50 / 0.05

b = 1000

Subtract 1000 from 5000: 5000 - 1000 = 4000

To learn more about linear functions, please check: brainly.com/question/26434260

#SPJ1

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Factor completely and then place the factors in the proper location on the grid. x2 + 13 x + 36
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Answer:

The factored form of this would be (x + 4)(x + 9)

Step-by-step explanation:

In order to determine the numbers in the parenthesis, we need to find numbers that multiply to the constant (36) and add up to the middle term (13). In order to do that, we list the factors of the constant and look for those that add up to 13.

1, 36

2, 18

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4, 9

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As you can see, 4 and 9 are the only pair that satisfy the stipulations. So we place them in a parenthesis with x's and express as the following.

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IS 0.7878 A TERMINATING Decimal
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If it continues its not if it stops it is.

Step-by-step explanation:

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What is the value of z in the table? A 4% peroxide solution is mixed with a 10% peroxide solution, resulting in 100 L of an 8% s
Tresset [83]

Answer:

87.1

Step-by-step explanation:

Lets say, first number = x


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Total = 49



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4 0
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find the mean, median, mode, and midrange. Then decide which you think is the most meaningful measure of average for that data s
marshall27 [118]

Answer:

mean = 254.6

median = 120

mode = 60

midrange = 958

For average data sets i prefer by finding the mean

Step-by-step explanation:

mean :

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median : 60 60 73 76 98 102 112 120 147 183 201 206 493 870 1018

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