Solve this please!!!!
1 answer:
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Answer:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
Where and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
And we have:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
<u><em>r=-199/80 is the right answer.</em></u> First, you had to multiply by 100 from both sides of the equation. And it gave us, . Next, you had to refine, and it gave us,
. Then, subtract by 1470 from both sides of equation. And it gave us,
. Simplify, and it gave us,
. You can also divide by 320 from both sides of equation. And it gave us,
. And finally, simplify, and it gave us the answer is <em><u>r=-199/80 is the right answer.</u></em> Hope this helps! And thank you for posting your question at here on brainly. And have a great day! -Charlie