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jeka94
2 years ago
13

If the law of demand applies to this good, then Q1 could be a. 100. b. 400. c. 200. d. 0.

SAT
1 answer:
irinina [24]2 years ago
4 0

If the law of demand applies to this good, then Q1 could be:

  • a. 0.

<h3>What is the law of demand?</h3>

The law of demand refers to the principle that states that the higher the price the lesser the quantity demanded.

So, if the price increases from $10 to $20 then the demand will drop from 100 to 0. If the price reduces, there will be more demand. So, option A is right.

Complete question:

Price: $10, $20

Quantity Demanded: 100, Q1

If the law of demand applies to this good, then Q1 could be

a. 0.

b. 100.

c. 200.

d. 400.

Learn more about the law of demand here:

brainly.com/question/1222851

#SPJ1

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The fathers age is the sum of the son and the mother ​
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Answer: The son is 1 year old and the father is 27 years old.

Explanation: Let’s call the sons age x and the fathers is y. You have the equations x+26=y and 3(x+8)=y=3x+24. So you could say that (3x-24)-(x+26)= z -z. So 2x-2=0. Add 2 to both sides and get 2x=2. x = 1 so the son is 1 year old

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Determine the total annual FICA tax for an annual salary of $38,480. A. $294. 37 b. $717. 96 c. $2,385. 76 d. $2,943. 72.
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d. $2,943.72 is the total annual FICA tax for an annual salary of $38,480.

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7 0
3 years ago
Serum cholesterol levels of 100 hypertensive patients were recorded. Mean cholesterol level was 190 mg/d1. The data was symmetri
xxTIMURxx [149]

The standard error is 1.5.

The range of 95% confidence interval is 160 mg/dL and 220 mg/dL

<h3>What is the standard error of the distribution?</h3>

The standard error of the distribution is calculated as follows:

  • Standard error = standard deviation/√N

where N is the number of participants = 100

From the empirical rule of a normal or symmetrical distribution;

  • 68% of the data lies within one standard deviation
  • 95% percent within two standard deviations, and
  • 99.7% within three standard deviations from the mean.

Therefore,  175 mg/dl and 205 mg/dl lie one standard deviation from the mean.

One standard deviation = 175 - 190 or 205 - 190 = ±15

Standard deviation = 15

a. Solving for the standard error using the equation above;

Standard error = 15/√100

Standard error = 1.5

b. The range of 95% confidence interval is two standard deviations away from the mean.

Range of values two standard deviations from the mean = 190 - (2*15) and 190 + (2 * 15)

Range of values two standard deviations from the mean = 160 mg/dL and 220 mg/dL

Therefore, the range of 95% confidence interval is 160 mg/dL and 220 mg/dL

In conclusion, the standard error is calculated from the standard deviation and the sample size.

Learn more about standard error at: brainly.com/question/14467769

#SPJ1

6 0
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