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coldgirl [10]
1 year ago
12

Array bounds checking should be directly coded into a system rather than assumed.

Computers and Technology
1 answer:
77julia77 [94]1 year ago
6 0

Answer:

True

Explanation:

One cannot assume an array bounds, it has to be specific

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What is the distance from the end of the pin to the center of the hole?
Lemur [1.5K]

Answer:

Roughly 7/8 on the pinhole, roughly 2-1/4" from the pinhole to end of the adapter.

Explanation:

8 0
2 years ago
Write a for loop to print all NUM_VALS elements of array hourlyTemp. Separate elements with a comma and space. Ex: If hourlyTemp
kondaur [170]

in c++

...

for(auto& el:hourlyTemp){

std::cout<<el<<", ";

}

...

This is called Range-based loop or for each loop

5 0
3 years ago
Create a new Java project/class called ChangeUp. Create an empty int array of size 6. Create a method called populateArray that
-Dominant- [34]
<h2>Answer:</h2><h2></h2>

//import the Random and Scanner classes

import java.util.Random;

import java.util.Scanner;

//Begin class definition

public class ChangeUp {

   

   //Begin the main method

  public static void main(String args[]) {

       //Initialize the empty array of 6 elements

      int [] numbers = new int [6];

       

       //Call to the populateArray method

       populateArray(numbers);

       

       

   } //End of main method

   

   

   //Method to populate the array and print out the populated array

   //Parameter arr is the array to be populated

   public static void populateArray(int [] arr){

       

       //Create object of the Random class to generate the random index

       Random rand = new Random();

       

       //Create object of the Scanner class to read user's inputs

       Scanner input = new Scanner(System.in);

       

       //Initialize a counter variable to control the while loop

       int i = 0;

       

       //Begin the while loop. This loop runs as many times as the number of elements in the array - 6 in this case.

       while(i < arr.length){

           

           //generate random number using the Random object (rand) created above, and store in an int variable (randomNumber)

           int randomNumber = rand.nextInt(6);

       

           //(Optional) Print out a line for formatting purposes

           System.out.println();

           

           //prompt user to enter a value

           System.out.println("Enter a value " + (i + 1));

           

           //Receive the user input using the Scanner object(input) created earlier.

           //Store input in an int variable (inputNumber)

           int inputNumber = input.nextInt();

           

           

           //Store the value entered by the user in the array at the index specified by the random number

           arr[randomNumber] = inputNumber;

           

           

           //increment the counter by 1

          i++;

           

       }

       

       

       //(Optional) Print out a line for formatting purposes

       System.out.println();

       

       //(Optional) Print out a description text

      System.out.println("The populated array is : ");

       

       //Print out the array content using enhanced for loop

       //separating each element by a space

       for(int x: arr){

           System.out.print(x + " ");

       }

   

       

  } //End of populateArray method

   

   

   

} //End of class definition

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining the lines of the code.

This source code together with a sample output has been attached to this response.

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
0d7446bcb6b48f78b8adbfa3da89789c.png
3 0
3 years ago
Find the number of ways in which a committee of 4 can be chosen from six boys and
natima [27]

Answer:

465 ways

Explanation:

Atleast 1 girl and 1 boy

Possible combinations :

1 girl ; 3 boys = 6C1 ; 6C3

2 girls ; 2 boys = 6C2 ; 6C2

3 girls ; 1 boy = 6C3 ; 6C1

(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)

Combination formula:

nCr = n! ÷ (n-r)!r!

We can also use a calculator :

6C1 = 6

6C3 = 20

6C2 = 15

Hence,

(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)

(6 * 20) + (15 * 15) + (20 * 6)

120 + 225 + 120

= 465 ways

6 0
3 years ago
Consider the following method, remDups, which is intended to remove duplicate consecutive elements from nums, an ArrayList of in
MAXImum [283]

Answer:

B. {1, 2, 2, 3, 3, 4, 5}

Explanation:

Given

The above code segment

Required

Determine which list does not work

The list that didn't work is B.\ \{1, 2, 2, 3, 3, 4, 5\}

Considering options (A) to (E), we notice that only list B has consecutive duplicate numbers i.e. 2,2 and 3,3

All other list do not have consecutive duplicate numbers

Option B can be represented as:

nums[0] = 1

nums[1] = 2

nums[2] = 2

nums[3] = 3

nums[4] = 3

nums[5] = 4

nums[6] = 5

if (nums.get(j).equals(nums.get(j + 1)))

The above if condition checks for duplicate numbers.

In (B), when the elements at index 1 and 2 (i.e. 2 and 2) are compared, one of the 2's is removed and the Arraylist becomes:

nums[0] = 1

nums[1] = 2

nums[2] = 3

nums[3] = 3

nums[4] = 4

nums[5] = 5

The next comparison is: index 3 and 4. Meaning that comparison of index 2 and 3 has been skipped.

<em>This is so because of the way the if statement is constructed.</em>

3 0
3 years ago
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