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2 years ago

Array bounds checking should be directly coded into a system rather than assumed.

Computers and Technology

1 answer:

77julia77 [94]2 years ago

6 0

Answer:

True

Explanation:

One cannot assume an array bounds, it has to be specific

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A programmer wants to determine whether a score is within 10 points of a given target. For example, if the target is 50, then th

Kipish [7]

Answer:

(target - 10 ≤ score) AND (score ≤ target + 10)

Explanation:

8 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST

Sergeeva-Olga [200]

I believe it’s boundaries

3 0

2 years ago

Read 2 more answers

Suppose users share a 1-Gbps link. Also, suppose each user requires 200 Mbps when transmitting, but each user only transmits 30

V125BC [204]

Answer:

The answer is "5 users and 1 block".

Explanation:

In Option a:

Bandwidth total $= 1-Gbps \times 1000$

$= 1,000 \ Mbps$

Any User Requirement $= 200 \ Mbps$

The method for calculating the number of approved users also is:

Now, calculate the price of each person for overall bandwidth and demands,

$\text{Sponsored user amount} = \frac{\text{Bandwidth total}}{\text{Each user's requirement}}$

$=\frac{1000}{200}\\\\=\frac{10}{2}\\\\= 5 \ users$

In Option b:

$\text{blocking probability} = \frac{link}{\text{1-Gbps} = 10^9 \frac{bits}{sec}}$

$\ let = 0.05 = \frac{100}{20} \\\\\text{blocking probability} = \frac{ 200 \times 10^6}{\frac{100}{20}}$

$= \frac{ 200 \times 10^6 \times 20 }{100}\\\\= \frac{ 2 \times 10^6 \times 20 }{1}\\\\= 40 \times 10^6 \\\\$

mean user $= 25 \times \frac{1}{20} \\\\$

$= 1.25$

max user $= \frac{10^9}{40 \times 10^6} \\\\$

$= \frac{10^9}{4 \times 10^7} \\\\ = \frac{10^2}{4} \\\\ = \frac{100}{4} \\\\= 25 \\\\ =\ \ 1 \ \ block \\\\$

3 0

3 years ago

Write a Raptor program that will generate a random number between 1 and 100; do not display the randomly generated number. Let t

zepelin [54]

Answer:

Explanation:

Let's do this in Python, we can first generate the random number from 1 to 100. Then compare that with the input number from the guesser.

from random import random

random_0_1 = random()

random_1_100 = 1 if round(100*random_0_1) < 1 else round(100*random_0_1)

for trial in range(3):

guess = input('Guess the number: ')

if guess == random_1_11:

print('You guessed correctly!')

break

else:

print(2 - trial + " remaining try")

8 0

3 years ago

Read 2 more answers

Given half a chance other people at work will take advantage of you

Damm [24]

have self-control and if you have a problem dont be afraid to speak your mind, show other people you mean buisness, but be polite to aviod starting more problems

3 0

3 years ago