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Dominik [7]
2 years ago
7

You want to put in a new concrete patio behind your house. You want it to be 12 ft wide by 14 ft long and it needs to be eight i

nches thick. You know that an 80 lb. bag of concrete yields 0.60 cubic feet. How many 80 lb. bags of concrete will you need for your patio?
Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
7 0

Answer:

You will need 187 80 pounds bags of concrete.

Step-by-step explanation:

12x14x(2/3) x 0.6 = 186.666 or 187

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which of the following temperatures is most precise? A) 45 degrees. B) 89.7 degrees. C) 80 degrees. D) 32.45 degrees
xxTIMURxx [149]
32.45 is most precise . Precise means how many points after decimal is reached. Accurate means how close your measurement of a value is that to the true value. Eg :Say 35cm is the measure of length of a body and a person got the measurement to be 34 . Another person2 got the measurement to be 32.88 . So in this case the first person has an accurate answer as he is close to the true value 35 , but person2 is more precise as he has two decimal places.
6 0
3 years ago
PLZ HELP!!! I Will give brainliest. What is the value of x in sin(3x)=cos(6x) if x is in the interval of 0≤x≤π/2
sertanlavr [38]

Answer:

sin(2x)=cos(π2−2x)

So:

cos(π2−2x)=cos(3x)

Now we know that cos(x)=cos(±x) because cosine is an even function. So we see that

(π2−2x)=±3x

i)

π2=5x

x=π10

ii)

π2=−x

x=−π2

Similarly, sin(2x)=sin(2x−2π)=cos(π2−2x−2π)

So we see that

(π2−2x−2π)=±3x

iii)

π2−2π=5x

x=−310π

iv)

π2−2π=−x

x=2π−π2=32π

Finally, we note that the solutions must repeat every 2π because the original functions each repeat every 2π. (The sine function has period π so it has completed exactly two periods over an interval of length 2π. The cosine has period 23π so it has completed exactly three periods over an interval of length 2π. Hence, both functions repeat every 2π2π2π so every solution will repeat every 2π.)

So we get ∀n∈N

i) x=π10+2πn

ii) x=−π2+2πn

iii) x=−310π+2πn

(Note that solution (iv) is redundant since 32π+2πn=−π2+2π(n+1).)

So we conclude that there are really three solutions and then the periodic extensions of those three solutions.

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