Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
The probability that they will pick neither the chocolate chip nor the walnut toppings is 0.3
We have
the total of all probabilities is 1.00, or 100%.
In the Venn diagram, we have the probabilities 0.2, 0.4 and 0.1; these sum to
0.2+0.4+0.1 = 0.6+0.1 = 0.7.
This leaves us 1.00-0.7 = 0.3 for the remaining probability of no toppings.
Learn more about Probability:
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Answer:
you have to set each factor to 0 and solve.
Step-by-step explanation:
Answer:
1. 46.125
Step-by-step explanation: Is your second one in the right format? I don't understand what it is asking. For the first one, however, you need to free the y being multiplied to 8 and so you are going to undo it by dividing 369 by 8.
See attached photo for answer.
