Can someone help me with this?

Translate the sentence into an equation<br>two more than the product of a number and 8 is 3.

Bingel [31]

Answer: 8x + 2 = 3

Step-by-step explanation: "two more than" means "add 2" which is +2

The product of 8 and a (unknown) number is 8x

Use the = sign in place of "is"

3 0

3 years ago

4. One morning at Jim's café, 25 people ordered juice, 10 ordered milk, and 50 ordered coffee with

Alona [7]

Answer:

D. 2 to 5

Step-by-step explanation:

10 milk orders to 25 juice orders can be simplified to 2:5 when divided by five.

8 0

2 years ago

Mr Black. 32 kg mg jars of peanut butter for school snacks. he spread the peanut butter on Bagels to feed 60 students. How many

hoa [83]

Answer:

Amount of peanut butter each student get = 533.34 gram (Approx.)

Step-by-step explanation:

Given:

Amount of peanut butter Mr black has = 32 kg

Total number of students = 60 students

Find:

Amount of peanut butter each student get

Computation:

Amount of peanut butter Mr black has = 32 kg

Amount of peanut butter Mr black has = 32 x 1,000 gram

Amount of peanut butter Mr black has = 32,000 gram

Amount of peanut butter each student get = Amount of peanut butter Mr black has / Total number of students

Amount of peanut butter each student get = 32,000 / 60

Amount of peanut butter each student get = 533.33

Amount of peanut butter each student get = 533.34 gram (Approx.)

4 0

3 years ago

If you multiply this number by 3 , then subtract 15 , the result is 51. What is the number?

bagirrra123 [75]

3x-15=51 3x=36 X= 12 Thus the number is 12

8 0

3 years ago

One thousand independent rolls of a fair die will be made. Compute an approximation to the probability that the number 6 will ap

pashok25 [27]

Answer:

0.19

Step-by-step explanation:

We are given that

Number of rolls of die=n=1000

Let the event of six coming up be success.Then, in each trial , the probability of success =p=P(success)=P(6)= $\frac{1}{6}$

Let X be the random variable for the number of sixes in the 1000 rolls of die.

Then, $X\sim Binom(1000,\frac{1}{6})$

Since, n is very large,the binomial random variable can be approximated as normal random variable.

Mean, $\mu=np=1000\times \frac{1}{6}=166.67$

Variance= $\sigma^2=np(1-p)=1000\times \farc{1}{6}\times (1-\frac{1}{6})=1000\times \frac{5}{36}=138.89$

$X\sim N(166.67,138.89)$

$P(150\leq X\leq 200)=P[\frac{150-166.67}{11.79}\leq \frac{X-\mu}{\sigma}\leq \frac{200-166.67}{11.79}]$

= $P[-1.41\leq Z\leq 2.83]=P[Z\leq 2.83]-P[Z$

= $\phi(2.83)-\phi(-1.41)$

=0.9977-0.0793=0.9184

Thus, the probability that the number 6 appears between 150 to 200 times=0.92

Now, given that 6 appears exactly 200 times .

Therefore, other number appear in other 800 rolls .

We have to find the probability that the number 5 will appear less than 150 times.

Therefore, for 800 rolls, let the event of 5 coming up be success.

Then , p=P(success)=P(5)= $\frac{1}{5}$

Let Y be the random variable denoting the number of times 5 coming up in 800 rolls.

Then, $Y\sim bin(800,\frac{1}{5})$

Mean, $\mu=np=800\times \frac{1}{5}=160$

Variance, $\sigma^2=np(1-p)=800\times \frac{1}{5}(1-\frac{1}{5})=128$

$Y\sim N(160,128)$ because n is large

$P(Y$

$P(Y$

Hence, the probability that the number 5 will appear less than 150 times given that 6 appeared exactly 200 times=0.19

4 0

2 years ago