Answer:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.
This means that 
95% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
<span>Break down every term into prime factors. ...Look for factors that appear in every single term to determine the GCF. ...Factor the GCF out from every term in front of parentheses, and leave the remnants inside the parentheses. ...<span>Multiply out to simplify each term. </span></span>
I guess it's 42
Hope it's helpful for you
Answer:
5% account = $1,240
10% account = $2,190
Step-by-step explanation:
Let's assume the amount of savings in the 5% account is x.
Thus the amount of savings in the 10% account is (x + $950).
We can write the following equation from the interest amount:
[5% x ] + [10% (x + $950)] = $281
5%x + 10%x + $95 = S281
15%x = $186
x = $1,240
There is $1,240 in the 5% account
Therefore, on the 10% account there is $1,240 + $950 = $2,190
