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Illusion [34]
2 years ago
11

A roller coaster’s height is given by the equation h = –.025t2 + 4t + 50, where t represents the time in seconds. How long will

it take riders to pass over the hill and reach ground level? Hint: Set h = 0.
Answer Options:

A.11.65

B.50.00

C.171.65

D.210.00
Mathematics
1 answer:
netineya [11]2 years ago
6 0

The time it took the rider to reach the ground level is 171.651seconds

<h3>Quadratic functions</h3>

Quadratic functions are functions that has a leading degree of 2.

Given the equation that represents  roller coaster’s height as shown

h = –0.025t^2 + 4t + 50

The coaster will reach the ground when h = 0

Substitute

0 = –0.025t^2 + 4t + 50

Factorize

On factorizing, the time it took the rider to reach the ground level is 171.651seconds

Learn more on quadratic function here: brainly.com/question/1214333

#SPJ1

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Answer:

  see below

Step-by-step explanation:

Each segment in ΔA"B"C" is 3 times the length of the corresponding segment in ΔABC. This is due to the dilation by a scale factor of 3.

Then you have ...

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Answer:

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Step-by-step explanation:

27.35 x 20/100

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=> $5.47

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Therefore, Option D is correct.

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4 years ago
In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
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Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

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Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

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What’s the domain and range of this graph ? PLEASE HELP URGENT
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