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aliina [53]
3 years ago
14

I need help please take a long and help me.

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
7 0

I believe the correct option is C after I checked it over and over again...

Sloan [31]3 years ago
5 0

The answer is c , I clicked that answer and got it right

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Find two consecutive even numbers such that the sum of the number and twice the greater number is 100
Romashka [77]
X+2(x+2)=100
x+2x+4=100
3x=100-4
3x=96
x=32

The answer is 32 and 34.
5 0
3 years ago
Read 2 more answers
14<br> Bolve for the value of z:<br> 5<br> Z<br> 25
Natalija [7]

Answer:

The answer is 15

Step-by-step explanation:

Thats what I got

3 0
3 years ago
Ali's dog weighs 8 times as much as her cat. Together, the two pets weigh 54 pounds. How much does Ali's dog weigh?
pantera1 [17]
Dog's weight = 48. That's the answer.

8 0
4 years ago
The solution to 5x = 55 is<br><br><br> x = 11<br><br><br> x = 50
Travka [436]

Answer:

x=11

Step-by-step explanation:

5x = 55

Divide each side by 5

5x/5 = 55/5

x = 11

4 0
3 years ago
Read 2 more answers
A high percentage of people who fracture or dislocate a bone see a doctor for that condition. Suppose the percentage is 99%. Con
marishachu [46]

Answer:

(i) 0.15708

(ii) 0.432488

(iii) 3

Step-by-step explanation:

Given that, 99% of people who fracture or dislocate a bone see a doctor for that condition.

There is only two chance either the person having fracture or dislocation of bone will either see the doctor or not.

As per previous data, if one person got a fracture or dislocation of bone, the chance of seeing the doctor is 0.99. Assuming this chance is the same for every individual, so the total number of people having fractured or dislocated a bone can be considered as Bernoulli's population.

Let p be the probability of success represented by the chances of not seeing a doctor by any one individual having fractured or dislocated a bone.

So, p=1-0.99=0.01

According to Bernoulli's theorem, the probability of exactly r success among the total of n randomly selected from Bernoulli's population is

P(r)=\binom{n}{r}p^r(1-p)^{n-r}\cdots(i)

(i) The total number of persons randomly selected, n=400.

The probability that exactly 5 of them did not see a doctor

So, r=5 , p=0.01

Using equation (i),

P(r=5)=\binom{400}{5}(0.01)^5(1-0.01)^{400-5}

=\frac{400!}{(400-5)!\times 5!}(0.01)^5(0.99)^{395}

=0.15708

(ii) The probability that fewer than four of them did not see a doctor

=P(r

=P(r=0)+P(r=1)+P(r=2)+P(r=3)

=\binom{400}{0}(0.01)^0(0.99)^{400}+\binom{400}{1}(0.01)^1(0.99)^{399}+\binom{400}{2}(0.01)^2(0.99)^{398}+\binom{400}{3}(0.01)^3(0.99)^{397}

=0.017951+0.072527+0.146154+0.195856

=0.432488

(iii) The expected number of people who would not see a doctor

=np

=300\times 0.01

=3

7 0
3 years ago
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