The length of side DF is 3.75.
Given that within the figure there are two triangles that are similar.
Congruent triangles will be triangles that have a comparable measure and shape. This infers that the comparing sides are comparable and the relating focuses are equivalent.
Two comparative triangles are given.
If two triangles are comparable at that point their comparing sides are relative and comparing points are congruent.
DF/AB=EF/BC
Substitute the values from the given figure
DF/15=6/24
Cross multiply both sides, and we get
DF×24=6×15
DF×24=90
Divide both sides by 24, we get
(DF×24)/24=90/24
DF=15/4
DF=3.75
Hence, the length of side DF from the given figure is 3.75.
Learn more about congruent triangles from here brainly.com/question/1675117
#SPJ1
