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olga nikolaevna [1]
3 years ago
7

Only the function represented by graph has inverse function

Mathematics
2 answers:
DedPeter [7]3 years ago
8 0

Answer:

need the graph to help

Step-by-step explanation:

KengaRu [80]3 years ago
3 0

Answer:

rest of the question?

Step-by-step explanation:

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Given the system of inequalities:
STatiana [176]
Slope intercept form : y = mx + b

4x - 5y < 1
-5y < -4x + 1
y > 4/5x - 1/5 <== slope intercept form

y - x > 3
y > x + 3 <== slope intercept form
8 0
3 years ago
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The model below is used to represent the area of a<br> square with a side length of /64 units.
Oxana [17]
8. Hope this helpsssss
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2 years ago
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Vadim26 [7]
Here is all the work with it

3 0
2 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
Using the distributive property to find the product (y — 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y
tatiyna
If you would like to find the value of a in the polynomial, you can do this using the following steps:

(y - 4)(y^2 + 4y + 16) = y^3 + 4y^2 + 16y - 4y^2 - 16y - 64 = y^3 + 4y^2 + ay - 4y^2 - ay - 64

a = 16

The correct result would be 16.
7 0
2 years ago
Read 2 more answers
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