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olga nikolaevna [1]
4 years ago
7

Only the function represented by graph has inverse function

Mathematics
2 answers:
DedPeter [7]4 years ago
8 0

Answer:

need the graph to help

Step-by-step explanation:

KengaRu [80]4 years ago
3 0

Answer:

rest of the question?

Step-by-step explanation:

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Answer:

C. 64

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What is the area of the shape shown?
Levart [38]
378 cm Is the correct answer i believe
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the length of a rectangle is 5 more than the width. the perimeter is 120 what is the length, width, and area?
KiRa [710]
The length is 50, the width is 20, and the area is 500. Here’s my work:

4 0
3 years ago
What is 2/3 dividend by 1/2?<br><img src="https://tex.z-dn.net/?f=%20%5Cdiv%20" id="TexFormula1" title=" \div " alt=" \div " ali
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Answer: one and one third 1 1/3

Step-by-step explanation:

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7 0
3 years ago
Select the functions that have a value of -1. sin180° cos180° tan180° csc180° sec180° cot180°
kupik [55]

We have to break each degree in terms of 90

A) sin180^\circ=sin(90\times2+0)

Which is in third quadrant, therefore sine is negative hence

sin(90\times2+0)= -sin0 ^\circ = 0


B) cos180^\circ =cos(90\times2+0)

Which is in third quadrant, therefore cosine is negative hence

cos(90\times2+0)= -cos0^\circ  = -1


C) tan180^\circ=tan(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

tan(90\times2+0)= tan0^\circ  = 0


D) csc180^\circ=csc(90\times2+0)

Which is in third quadrant, therefore cosec is negative hence

cosec(90\times2+0)= -csc0^\circ  =not defined


E)sec180^\circ=sec(90\times2+0)

Which is in third quadrant, therefore secant is negative hence

sec(90\times2+0)= -sec0^\circ  = -1


F) cot180^\circ=cot(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

cot(90\times2+0)= cot0^\circ = not defined


Hence only cos 180^\circ and

sec180^\circ have value -1

Hope this will help

7 0
3 years ago
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