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1 year ago

6

In algebra, we transfer these same skills to expressions involving variables. what elementary skills have you used so far in thi

s course, and how have you extended them?

1 answer:

kirza4 [7]1 year ago

3 0

Input a picture possibly? then i’ll be able to answer…

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Help don’t understand

marusya05 [52]

Answer:

f(-14) = -6

f(-4) = 6

f(12) = 6

f(0) = -3

negative

Step-by-step explanation:

f(-14) = -6

This is because when x is -14, y is -6, as seen in the graph

f(-4) = 6

This is because when x is -4, y is 6, as seen in the graph

f(12) = 6

This is because when x is 12, y is 6, as seen in the graph

f(0) = -3

This is because when x is 0, y is -3, as seen in the graph

is f(4) positive or negative?
negative

This is because when x is 4, y is -6, as seen in the graph

6 0

1 year ago

Which functions have a horizontal asymptote? Y = f(x) y = h(x) y = g(x) y = k(x) On a coordinate plane, 4 exponential functions

Fed [463]

Answer:

Is all of them !!

Step-by-step explanation:

Because they all have asymptote

5 0

3 years ago

Read 2 more answers

Find the distance between the pair of points.

SVEN [57.7K]

Answer:

Distance is $\sqrt{290}$ units

Step-by-step explanation:

Use the distance formula which is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$

We are given that $(x_1,y_1)$ is $(-6,-23)$ and $(x_2,y_2)$ is $(-23,-24)$ , therefore the distance between the two points is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}$

$d=\sqrt{(-23+6))^2+(-24+23))^2}$

$d=\sqrt{(-17)^2+(-1)^2}$

$d=\sqrt{289+1}$

$d=\sqrt{290}$

Therefore, the distance between $(-6,-23)$ and $(-23,-24)$ is $\sqrt{290}$ units.

3 0

2 years ago

The formula for finding the area of a circle is a equals pi r square. solve the formula for r.

Reika [66]

I hope this helps you

Area=pi.r^2

r^2=Area/pi

r= square root of Area/pi

5 0

3 years ago

Perform the indicated operations. give answers in simplified form.<br><br> √9/25

tino4ka555 [31]

$\sqrt{\frac{9}{25}} = \frac{\sqrt{9}}{\sqrt{25}} = \frac{3}{5}$

8 0

2 years ago