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Ymorist [56]
2 years ago
11

This table reflects the result of a survey conducted in a town to find out the number of cars of a particular color.

Mathematics
1 answer:
inysia [295]2 years ago
6 0

the range that would be the most appropriate to represent the numerical data on the vertical axis is B. 20 to 100.

<h3>what range would be most appropriate?</h3>

the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.

this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.

find out more on bar graph ranges at brainly.com/question/25196929.

#SPJ1

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Please can someone help me with this question?
zhannawk [14.2K]

Answer:

a = 16 π cm²      Exact answer

a = 50.24 cm²       Decimal approximation

Step-by-step explanation:

Radius of the circle

16/2 = 8

Area of the circle

a = πr²

a = π4²

a = 16 π cm²      Exact answer

a = 16 * 3.14

a = 50.24 cm²       Decimal approximation

7 0
3 years ago
What is the approximate length of VU? What is the length of the midsegment parallel to VU?
anastassius [24]

u is at (1,-2)

V is at (-6,-6)

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6 0
3 years ago
How do i do this? and what’s the answer?
Trava [24]
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8 0
3 years ago
In isosceles △ABC the segment BD (with D∈ AC ) is the median to the base AC . Find BD, if the perimeter of △ABC is 50m, and the
Morgarella [4.7K]

Let the equal sides of the isosceles Δ ABC be x.

Given that the perimeter of Δ ABC = 50m.

Therefore, 2x + AC = 50 --- (1)

It is also given that the perimeter of Δ ABD = 40m.

Therefore, x + BD + AD = 40

BD is the median of the Δ ABC. Therefore, D is the midpoint of AC.

So AD = CD.

Or, AD = \frac{1}{2} AC

Therefore, x + BD + \frac{1}{2} AC = 40

Multiply both sides by 2.

2x + 2BD + AC = 80

From (1), 2x + AC = 50.

Therefore, 2BD + 50 = 80

2BD = 80 - 50

2BD = 30

BD = 15m.

6 0
3 years ago
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What is 54x10 to the power of 3
denis23 [38]
54000

54 x (10^3) = 54000
8 0
3 years ago
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