First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps<span />
Answer:
1/3
(given answers in Question are unreadable)
Step-by-step explanation:
We search for red balls (neither yellow or black). There are 6 red balls among all 18 balls. Selecting one ball, there is a chance 6/18 that we pull out a red one. 6/18 is the same as 1/3.
Answer:
3,6 or 4,6?
Step-by-step explanation:
Answer:
the answer is 45
Step-by-step explanation:
Answer:
v = 9/2 + sqrt(61)/2 or v = 9/2 - sqrt(61)/2
Step-by-step explanation:
Solve for v over the real numbers:
-v^2 + 9 v - 5 = 0
Multiply both sides by -1:
v^2 - 9 v + 5 = 0
Subtract 5 from both sides:
v^2 - 9 v = -5
Add 81/4 to both sides:
v^2 - 9 v + 81/4 = 61/4
Write the left hand side as a square:
(v - 9/2)^2 = 61/4
Take the square root of both sides:
v - 9/2 = sqrt(61)/2 or v - 9/2 = -sqrt(61)/2
Add 9/2 to both sides:
v = 9/2 + sqrt(61)/2 or v - 9/2 = -sqrt(61)/2
Add 9/2 to both sides:
Answer: v = 9/2 + sqrt(61)/2 or v = 9/2 - sqrt(61)/2
