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Luden [163]
1 year ago
9

I need help with this!!

Mathematics
2 answers:
kompoz [17]1 year ago
4 0

Answer: $18.51

Step-by-step explanation:
1015cm^3/7.95cm^3/g = 127.67g

127.67g/1000g = .128

.128*$.29 = $.037

$.037*500 = $18.51

olga2289 [7]1 year ago
3 0

Answer:

$1170

Step-by-step explanation:

1. We know that each steel part has a volume of 1015 cubic centimeters, and the machinist wants to make 500 of these. Then the total volume of the steel part the machinist will make will be 1015 x 500.

--> 1015 x 500

--> 507500 cubic centimeters.

2. The density of the steel part is 7.95 grams per one cubic centimeter. Then the total density of the 500 steel parts will be 507500 x 7.95.

--> 507500 x 7.95

--> 4,034,625 grams.

3. For every kilo of steel part, the cost is $0.29. We should first change the 4,034,625 gram to kilo. Since 1000 grams is a kilo, we divide 4,034,625 by 1000.

--> 4,034,625 grams / 1000 = 4034.625 kilograms.

Now we multiply 4034.625 by 0.29 to find the total cost.

--> 4034.625 x 0.29

--> 1170.04125.

Since the question specifically asked to round it to the nearest dollar, our final answer becomes $1170.

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Answer:

3/4

Step-by-step explanation:

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3 years ago
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Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
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Marrrta [24]

The answer would be B. Edge

The set of points in space that are a given distance from a given point is called an <u>Edge.</u>

D would be incorrect since it doesn’t have any edges and is like a circle but is 3D. A cylinder is also incorrect since it has curves from top to bottom. C is also incorrect since it only shows one side, which is called the face. That leaves you with edge which would be the correct answer.


Hope this helps! :3

8 0
3 years ago
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