Answer:
<em>Thus, the dimensions of the metal plate are 10 dm and 8 dm.</em>
Step-by-step explanation:
For a quadratic equation:
The sum of the roots is -b and the product is c. Note the leading coefficient is 1.
We know the perimeter of the rectangular metal plate is 36 dm and its area is 80 dm^2. Being L and W its dimensions, then:
P=2(L+W)=36
A=L.W=80
Note both formulas are closely related to the roots of the quadratic equation, we only need to adjust the data for the perimeter to be exactly the sum of L+W and not double of it.
Thus we use the semi perimeter instead as P/2=L+W=18
The quadratic equation is, then:
Factoring by finding two numbers that add up to 18 and have a product of 80:
The solutions to the equation are:
x=10, x=8
Thus, the dimensions of the metal plate are 10 dm and 8 dm.
Answer:
Answer below
Step-by-step explanation:
Point D: (-6,-1)
Point C: (-3,0)
Point B: (-3,6)
Point A: (0,0)
Answer:
hope so
Step-by-step explanation:
20+2x-8
12+2x
hope this helps
srry if wrong
(9,-36)
X=9 Y= -36
-3x-9=1/3x-39
Solve it
The answer is x=9
Y=-3x-9
Y= -3(add the 9 because 9 is equal x) -9
Y=-3(9)-9
Solve it
The answer is y=-36
Answer:
Step-by-step explanation:
<u>Roots of a polynomial</u>
If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula
Where a is an arbitrary constant.
We know three of the roots of the degree-5 polynomial are:
We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:
Let's build up the polynomial, assuming a=1:
Since:
Operating the last two factors:
Operating, we have the required polynomial:
