Answer:
0.8
Step-by-step explanation:
The question here says that In a class of 30 students, 18 are men, 6 are earning a B, and no men are earning a B. If a student is randomly selected from the class, find the probability that the student is a man or earning a B.
Since the question says that 18 out of 30 students are men,6 out of the remaining people earn a "B" and non of the 18 men earn a "B".
The probability of picking a man or a person that earns a "B" is
18/30 (since there are 18 men out of the 30 students)
And 6/30(since there are 6 people that earn a "b")
The probability of picking a man or a "b" earner is
18/30 + 6/30
= 24/30 or 0.8
This was written using the associative property.
(7+5) +2 equals 12+2 which equals 14.
7 +(5+2) equals 7+7 which equals 14.
The answer for this one is 3/11.
*If you need an explanation, leave a comment down below, and I will give you the explanation.
10. D: x=4, 8, 12 discrete
11. D: 6>x>0 Continuous