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Murrr4er [49]
3 years ago
5

A scientist claims that a smaller proportion of members of the National Academy of Sciences are women when compared to the propo

rtion of women nationwide. Let p1 represent the proportion of women in the National Academy of Sciences and p2 represent the proportion of women nationwide. Which is the correct alternative hypotheses that corresponds to this claim?
A.Ha: p1 - p2 < 0
B.Ha: p1 - p2 > 0
C.Ha: p1 - p2 ? 0
Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0

Answer:

Correct option: (A) <em>p</em>₁ - <em>p</em>₂ < 0.

Step-by-step explanation:

The claim made by the scientist is that the proportion of female members of the National Academy of Sciences is less than the proportion of female members nationwide.

To test this claim we can difference between two proportions <em>z</em>-test.

It is assumed that <em>p</em>₁ is the proportion of women in the National Academy of Sciences and <em>p</em>₂ is the proportion of women nationwide.

Then we nee to test whether <em>p</em>₁ - <em>p</em>₂ < 0 or not.

The hypothesis can be defined as:

<em>H₀</em>: The proportion of women in the National Academy of Sciences is not less than the proportion nationwide, i.e. <em>p</em>₁ - <em>p</em>₂ ≥ 0.

<em>H₀</em>: The proportion of women in the National Academy of Sciences is less than the proportion nationwide, i.e. <em>p</em>₁ - <em>p</em>₂ < 0.

Thus, the correct option is (A).

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Answer:

51/4

Step-by-step explanation:

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D(x) =\left\{ \begin{array}{ll}  x  & \mbox{if } 0\leq x \leq 20 \\  x-20 & \mbox{if } 20\leq x < 45\\                70-x & \mbox{if } 45 \leq x \leq 70\\                x-70 & \mbox{if } 70 \leq x \leq 100\\ \end{array}\right.

Now, as we said before X represents the random variable where the bus breaks down, then we form a new random variable Y = D(X), Y is a random variable as well, remember that there is a theorem that says that

E[Y] = E[D(X)] = \int\limits_{-\infty}^{\infty} D(x) f(x) \,\, dx

Where f(x) is the probability mass function of X. Using the information of our problem

E[Y] = \int\limits_{-\infty}^{\infty}  D(x)f(x) dx \\= \frac{1}{100} \bigg[ \int\limits_{0}^{20} x dx +\int\limits_{20}^{45} (x-20) dx +\int\limits_{45}^{70} (70-x) dx +\int\limits_{70}^{100} (x-70) dx  \bigg]\\= \frac{51}{4} = 12.75

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