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3 years ago

Sec^2xcotx-cotx=tanx

Mathematics

1 answer:

gavmur [86]3 years ago

5 0

$sec^2x\cot x-\cot x=\cot x(\sec^2x-1)=\cot x\tan^2x=\tan x$

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For the following system, if you isolated x in the second equation to use the Substitution Method, what expression would you sub

LekaFEV [45]

Isolate x in 2nd equation...

-x - 2y = -10 ....add 2y to both sides
-x = 2y - 10 ...multiply by -1 to make x positive
x = -2y + 10 <== u would sub in -2y + 10 in for x in the 1st equation

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3 years ago

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The total amount of money (in cents) of x dimes and (x+6) nickels

forsale [732]

Answer:

60 cents

Step-by-step explanation:

10x + 5(x+6)

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3 years ago

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Solve the following equation

jok3333 [9.3K]

Answer: $\frac{- 1}{11}$

Step-by-step explanation:

Note: the "." symbol stands for multiplication

Given,

$\frac{2x+4}{3} \\$ - $\frac{5x-7}{2}$ = 5

First we the LCM = 6,

$\frac{2(2x+4)}{2.3}$ - $\frac{3(5x-7)}{3.2}$ = 5

Then, we join both sides, since they have same denominator

$\frac{2(2x+4) - 3(5x-7)}{6}$ = 5

Multiply again

$\frac{4x+8 - 15x+21}{6}$ = 5

Add the same numbers

$\frac{-11x + 29}{6}$ = 5

Transpose 6 to the other side

-11x + 29 = 5.6

-11x + 29 = 30

Transpose 29 to the other side

-11x = 30 -29

-11x = 1

Transpose 11 to the other side to get answer

x = $\frac{-1}{11}$

Hope it helps! If you have any doubts, feel free to ask

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2 years ago