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tamaranim1 [39]
3 years ago
7

What is 10x+3-6x simplify

Mathematics
2 answers:
uranmaximum [27]3 years ago
6 0
The answer is 4x+3.

Hope this helps ;)
Mademuasel [1]3 years ago
4 0
4x + 3

Hope this helped :)
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2(5x + 3) -x + 3 = 18
Dvinal [7]

Answer:

x = 1

Step-by-step explanation:

7 0
3 years ago
What two-digit numbers greater than 69 are divisible by 2 and 11?
Mariulka [41]
88... 88/11=8 and 88/2=44
8 0
3 years ago
2.) Fill in the blank.
Montano1993 [528]

Answer:

E.) 1

Step-by-step explanation:

Firstly we will solve for L.H.S.

L.H.S. =Csc^2\theta

Since we know that Csc^2\theta is the inverse of Sin^2\theta.

So we can say that;

csc^2\theta=\frac{1}{sin^2\theta}

Now For R.H.S.

Cot^2\theta+1

Since we  can rewrite cot^2\theta as \frac{cos^2\theta}{sin^2\theta}.

Now we can say that the R.H.S. is;

\frac{cos^2\theta}{sin^2\theta}+1

Now we add the fraction and get;

\frac{cos^2\theta+sin^2\theta}{sin^2\theta}

Now according to trigonometric identity;

cos^2\theta+sin^2\theta=1

So, \frac{cos^2\theta+sin^2\theta}{sin^2\theta}=\frac{1}{sin^2\theta}

Here,

csc^2\theta=\frac{1}{sin^2\theta}   and     Cot^2\theta+1 = \frac{1}{sin^2\theta}<em>  </em>

L.H.S. = R.H.S.

Hence csc^2\theta=cot^2\theta+1

4 0
3 years ago
Suppose a change of coordinates T:R2→R2 from the uv-plane to the xy-plane is given by x=e−2ucos(5v), y=e−2usin(5v). Find the abs
anzhelika [568]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The solution is  \frac{\delta  (x,y)}{\delta (u, v)} | = 10e^{-4u}

Step-by-step explanation:

From the question we are told that

        x =  e^{-2a} cos (5v)

and  y  =  e^{-2a} sin(5v)

Generally the absolute value of the determinant of the Jacobian for this change of coordinates is mathematically evaluated as

     | \frac{\delta  (x,y)}{\delta (u, v)} | =  | \ det \left[\begin{array}{ccc}{\frac{\delta x}{\delta u} }&{\frac{\delta x}{\delta v} }\\\frac{\delta y}{\delta u}&\frac{\delta y}{\delta v}\end{array}\right] |

        = |\ det\ \left[\begin{array}{ccc}{-2e^{-2u} cos(5v)}&{-5e^{-2u} sin(5v)}\\{-2e^{-2u} sin(5v)}&{-2e^{-2u} cos(5v)}\end{array}\right]  |

Let \   a =  -2e^{-2u} cos(5v),  \\ b=-2e^{-2u} sin(5v),\\c =-2e^{-2u} sin(5v),\\d=-2e^{-2u} cos(5v)

So

     \frac{\delta  (x,y)}{\delta (u, v)} | = |det  \left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] |

=>    \frac{\delta  (x,y)}{\delta (u, v)} | = | a *  b  - c* d |

substituting for a, b, c,d

=>    \frac{\delta  (x,y)}{\delta (u, v)} | =  | -10 (e^{-2u})^2 cos^2 (5v) - 10 e^{-4u} sin^2(5v)|

=>   \frac{\delta  (x,y)}{\delta (u, v)} | =  | -10 e^{-4u} (cos^2 (5v)   + sin^2 (5v))|

=>  \frac{\delta  (x,y)}{\delta (u, v)} | = 10e^{-4u}

7 0
3 years ago
The function y=x²-4x+8 approximates the height, y, of a bird, and its horizontal distance, x, as it flies from one
trapecia [35]

When the bird is 2 feet away from the first fence post, it reaches its minimum height of 4 feet  , Minimum at (2,4)

Therefore Option C and D is the correct answer.

<h3>What is a Quadratic Function?</h3>

The equation for a quadratic function is given by

y = a(x-h)² +k²

where (h,k) is the extreme value(vertex).

Here the equation given is

y = x²-4x +8

y = x²-4x+4+4

y = (x-2)² +4

Here the value of a = 1 , h = 2 and k = 4

The extreme value is at (2,4)

Therefore When the bird is 2 feet away from the first fence post, it reaches its minimum height of 4 feet  , Minimum at (2,4)

Therefore Option C and D is the correct answer.

To know more about Quadratic Function

brainly.com/question/5975436

#SPJ1

7 0
2 years ago
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