All categories

1 year ago

What’s the volume of a rectangle solid with the given dimensions: length 20, width 23, height 26

Mathematics

1 answer:

ANEK [815]1 year ago

8 0

The volume of the rectangular solid is: 11,960 units³.

<h3>How to Find the Volume of a Rectangular Solid?</h3>

The formula to find the volume of a rectangular solid is: (length)(width)(height).

Given the dimensions as:

Length = 20 units
Width = 23 units
Height = 26 units

Volume = (20)(23)(26)

Volume of the rectangular solid = 11,960 units³.

Learn more about about the volume of rectangular solid on:

brainly.com/question/15116803

#SPJ1

You might be interested in

Is -134 greater than or less than 1136

masya89 [10]

Answer:

less than.

Step-by-step explanation:

.............

7 0

2 years ago

Help on these two plz help asp it's due tomorrow plz

zimovet [89]

Answer:

a = 615

Step-by-step explanation:

3 0

3 years ago

DeSean is sorting his toy car collection. ⅔ of the cars are sports cars. ¼ of the remaining toys are pick up trucks. All of the

user100 [1]

Answer:

Fraction of fire trucks = $\frac{1}{4}$

Total number of toy cars = $16$

Step-by-step explanation:

Fraction of sports car = $\frac{2}{3}$

Fraction of remaining cars $=1-\frac{2}{3}=\frac{3-2}{3} =\frac{1}{3}$

So,

Fraction of pick up cars = $\frac{1}{4}(\frac{1}{3})=\frac{1}{12}$

Therefore,

Fraction of fire trucks = $\frac{1}{3}-\frac{1}{12}=\frac{4-1}{12}=\frac{3}{12}=\frac{1}{4}$

That is Number of fire trucks = $\frac{1}{4}$ ( Total number of toy cars )

Number of fire trucks = 4

Total number of toy cars = $4(4)=16$

3 0

2 years ago

Find each number. round to the nearest tenth if necessary. What percent of 16 is 12?

kvasek [131]

.16x=12 x= 12/.16. x=75

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2

PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given Trigonometric expression is

$\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }$

So, on rationalizing the denominator, we get

$\rm \: = \: \dfrac{sin\theta }{1 + cos\theta } \times \dfrac{1 - cos\theta }{1 - cos\theta }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) = {x}^{2} - {y}^{2} \: }}}$

So, using this, we get

$\rm \: = \: \dfrac{sin\theta (1 - cos\theta )}{1 - {cos}^{2}\theta }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {sin}^{2}x + {cos}^{2}x = 1}}}$

So, using this identity, we get

$\rm \: = \: \dfrac{sin\theta (1 - cos\theta )}{{sin}^{2}\theta }$

$\rm \: = \: \dfrac{1 - cos\theta }{sin\theta }$

<u>Hence, </u>

$\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta } = \: \dfrac{1 - cos\theta }{sin\theta } }}} \\$

3 0

2 years ago

Read 2 more answers